How can i do this:
In:
a = [{'10100': u'Z'}, {u'00101': u'C'}, {u'01100': u'B'}, {u'00111': u'T'}]
Out:
a = [{u'01100': u'B'}, {u'00101': u'C'}, {u'00111': u'T'}, {'10100': u'Z'}]
I mean in order to value
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1Why `dict`s instead of `tuple`s? ex. `{'10100': u'Z'}` -> `('10100', u'Z')` – internet_user Jan 17 '18 at 20:53
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Can you post the code that you've tried thus far? – Preston Martin Jan 17 '18 at 20:54
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Related: https://stackoverflow.com/questions/72899/how-do-i-sort-a-list-of-dictionaries-by-values-of-the-dictionary-in-python – Ilja Everilä Jan 17 '18 at 20:56
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`sorted(a, key=lambda k: k.values())` – chickity china chinese chicken Jan 17 '18 at 21:01
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@Stack Nah, that one has a shared key by which to compare. This one doesn't. – Stefan Pochmann Jan 17 '18 at 21:03
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1@davedwards `sorted(a, key=dict.values)` – Stefan Pochmann Jan 17 '18 at 21:03
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Just use `tuple` objects... `dict` doesn't make any sense – juanpa.arrivillaga Jan 17 '18 at 21:04
1 Answers
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You can use dict.values() in the sorting key:
a = [{'10100': u'Z'}, {u'00101': u'C'}, {u'01100': u'B'}, {u'00111': u'T'}]
new_a = sorted(a, key=lambda x:x.values()[0])
Output:
[{u'01100': u'B'}, {u'00101': u'C'}, {u'00111': u'T'}, {'10100': u'Z'}]
Ajax1234
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