How Split a string in Java

Question

I have a string which is (30) can someone please help me to split it as below

(
32
)

My concern is there is no spaces between the brackets and number. After splitting I wants to store each and every character to separate variable and I want to convert "32" in to integer value to use it

@jens i am not expecting u to do my work, i am not an expert so that i have raised a question — Narendra Chetan, Jan 18 '18 at 06:53
Part of a question should be an attempt to solve your Problem. Read [ask] — Jens, Jan 18 '18 at 06:57

score 1 · Answer 1 · answered Jan 18 '18 at 06:37

1

One option uses lookarounds to determine where the split should take place. Assuming that you want a split to happen at the boundary between a word a non word character, lookarounds would work because they assert but do not consume, leaving all the input to appear in the result.

String input = "(32)";
String[] parts = input.split("(?<=[^A-Za-z0-9])(?=[A-Za-z0-9])|(?<=[A-Za-z0-9])(?=[^A-Za-z0-9])");
for (String part : parts) {
    System.out.println(part);
}

(
32
)

Demo

answered Jan 18 '18 at 06:37

Tim Biegeleisen

502,043
27
286
360

I didn't get u please help me in detail – Narendra Chetan Jan 18 '18 at 06:40
@NarendraChetan Your question has been closed because it is unclear what you are asking. Edit your question and tell us the logic by which your input gets split the way that it does. My answer is correct, under certain assumptions. – Tim Biegeleisen Jan 18 '18 at 06:41

Gnanasekaran Palanisamy · Answer 2 · 2018-01-18T07:06:59.563

1

Regex pattern "\\b" is used match word separated by delimiter.

public class Main {
    public static void main( String[] str ) {

        String[] split = splitStr( "(32)" );
        for ( String s : split ) {
            System.out.println(s);
        }
    }

    public static String[] splitStr( String str ) {
        String regex = "\\b";
        return str.split(regex);
    }
}

edited Jan 18 '18 at 07:06

answered Jan 18 '18 at 06:48

Gnanasekaran Palanisamy

887
5
7

Do not add Code without explanation. It is not helpful. – Jens Jan 18 '18 at 06:56

score 0 · Accepted Answer · answered Jan 18 '18 at 06:36

0

Try as follows use toCharArray()

String str = "(32)";

char[] chars = str.toCharArray();

System.out.println(chars[0]);
System.out.println(chars[1]);
System.out.println(chars[2]);
System.out.println(chars[3]);

answered Jan 18 '18 at 06:36

Nisal Edu

7,237
4
28
34

may i know in detail please. as i am not an expert in java basically i am a tester and implementing automation – Narendra Chetan Jan 18 '18 at 06:39
After splitting can i store each character in to any other variable – Narendra Chetan Jan 18 '18 at 06:43
@NarendraChetan when you use toCharArray your String seperate to it's character level and store in char array. – Nisal Edu Jan 18 '18 at 06:44
@NarendraChetan yes you can use as follows char a = chars[0] like wise – Nisal Edu Jan 18 '18 at 06:45
1

it works for me thanks a lot. I appreciate your support and timely help – Narendra Chetan Jan 18 '18 at 07:52

eis · Answer 4 · 2018-01-18T06:45:57.017

It seems you want to keep the split characters as well, so using String.split() 'normally' will not do. For that, I would go with lookarounds already proposed, but with a simpler pattern:

import java.util.Arrays;

public class Splitter {
  public static void main(String args[]) {
    String str = "(30)";
    String[] results = str.split("(?<=[()])|(?=[()])");
    System.out.println(Arrays.toString(results)); // [(, 30, )]
  }
}

This pattern will use characters '(' and ')' as tokens to use for splitting, but keeps the tokens as well.

If you're interested, there's more discussion on using lookarounds in this thread.

How Split a string in Java

4 Answers4

Demo