Not sure about this syntax error

Question

I have this page where the administrator approves/rejects employee leaves.

Leave Details

I'm trying to make approve/reject show up under status when I click on it. I followed the exact same code on the tutorial, apparently I do have a syntax error. The error was "Parse error: syntax error, unexpected '}'"

Here's my code:

 <body>
  
<?php 
if(isset($_POST['approved']))
{
  echo "approved";
  $status=$_POST['status']
}
if(isset($_POST['rejected']))
{
  echo "rejected";
  $status=$_POST['status']
}
?>
 
    <!-- Begin page content -->
    <div class="container">
      <div class="page-header">

<h3>
 Employee Leaves
</h3>
   <div class="table-responsive">
    <table class="table">
     <tr>
      <th>Employee Name</th>
      <th>Phone</th>
      <th>Email</th>
      <th>From</th>
      <th>To</th>
      <th>Reason</th>
      <th>Status</th>
      <th>---</th>
     </tr>
    <?php
     include ('database.php');
     $result = $database->prepare ("SELECT * FROM leaves order by id DESC");
     $result ->execute();
     for ($count=0; $row_message = $result ->fetch(); $count++){
    ?>
     <tr>
      <td><?php echo $row_message['full_name']; ?></td>
      <td><?php echo $row_message['phone']; ?></td>
      <td><?php echo $row_message['email']; ?></td>
      <td><?php echo $row_message['fromdate']; ?></td>
      <td><?php echo $row_message['todate']; ?></td>
      <td><?php echo $row_message['reason']; ?></td>
      <td><?php echo $row_message['status']; ?></td>
      <td>
      <form method="post" action=""><button type="submit" name="approved">Approve</button></form>
      &nbsp
      <form method="post" action=""><button typ="submit" name="rejected">Reject</button></form>
      </td>
     </tr>
     <?php } ?>
    </table>
    
    <a href="home"><button type="button" class="btn btn-primary"><i class="glyphicon glyphicon-arrow-left"></i> Back</button></a>
    
   </div>
  </div>

that title needs work – Funk Forty Niner Jan 18 '18 at 14:55 — Funk Forty Niner, Jan 18 '18 at 14:55

Jonny · Accepted Answer · 2018-01-18T15:00:17.577

0

In php you always have to close off your lines with a ;. You forgot to add 2 ;.

 if(isset($_POST['approved']))
 {
  echo "approved";
  $status=$_POST['status'];
}
if(isset($_POST['rejected']))
{
echo "rejected";
$status=$_POST['status'];
}

edited Jan 18 '18 at 15:00

answered Jan 18 '18 at 14:56

Jonny

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Thank you! Accepting your ans in 10 mins – John Z Jan 18 '18 at 14:59
no problem glad to help – Jonny Jan 18 '18 at 15:02
Btw I'm getting an undefined index in the same code I posted – John Z Jan 18 '18 at 15:03
you need to change typ="submit to type=submit on your second form. and im looking into the undefined index. – Jonny Jan 18 '18 at 15:07
Oh thank you so much. I hope you could help me with the undefined index – John Z Jan 18 '18 at 15:10
what line is the error on can you copy and paste it? – Jonny Jan 18 '18 at 15:18
It's okay, i'll just figure it out :) – John Z Jan 18 '18 at 15:22

Not sure about this syntax error

1 Answers1