I am trying to parse the POST request sent by the App Engine blobstore handler in development to get the Google Cloud Storage file path ('/gs/...') using Flask. Webapp2 has a method to get this if you inherit from blobstore_handlers.BlobstoreUploadHandler :- self.get_file_infos(). This method is not available in Flask.
This is a sample of the raw request data in Flask using request.get_data():
--===============0287937837666164318==
Content-Type: message/external-body; blob-key="encoded_gs_file:ZnBscy1kZXYvZmFrZS1nVTFHNFdrc3hobUFoaEtWVEVmNHZnPT0="; access-type="X-AppEngine-BlobKey"
Content-Disposition: form-data; name="file"; filename="Human Code Reviews One.pdf"
Content-Type: application/pdf
Content-Length: 951486
Content-MD5: NzNhOTI0YjdjNTFiMjEyYmY0NDUzZGFmYzBlOTExNTY=
X-AppEngine-Cloud-Storage-Object: /gs/appname/fake-gU1G4WksxhmAhhKVTEf4vg==
content-disposition: form-data; name="file"; filename="Human Code Reviews One.pdf"
X-AppEngine-Upload-Creation: 2018-01-22 12:26:08.095166
--===============0287937837666164318==--
I have tried both msg = email.parser.Parser().parsestr(raw_data) and msg = email.message_from_string(raw_data) but msg.items() return an empty list.
If I do rd = raw_data.split('\r\n') and parse a line containing a proper header I get what I want for that line: [('X-AppEngine-Cloud-Storage-Object', '/gs/appname/fake-gU1G4WksxhmAhhKVTEf4vg==')].
The issue is how to do this for the entire string and skip the blank and boundary lines.
For now, I am using the following code but I can't help but think there's a way to do this without reinventing the wheel:
for line in raw_data.split('\r\n'):
if line.startswith(blobstore.CLOUD_STORAGE_OBJECT_HEADER):
gcs_path = line.split(':')[1].strip()
Thank you.
Edit:
This question is not a duplicate of the one here (How to get http headers in flask?) because I have a raw string (called a field header, see the boundary delimiters not present in HTTP headers) I would like to parse into a dictionary.
