Why in Fat arrow functions arguments object is undefined

Question

If we print the output of arguments variable inside a normal function:

var func = function() { console.log(arguments); }
func();

The result is an object which contains information about the context (parameter values, scope , functionLocation...)

But if we reproduce the same function with fat arrow, we will never get argument declared:

var func = () => { console.log(arguments); }
func();

// arguments is not defined

Can anyone explain how can we get the context data from arrow functions?

callee, caller and length. They are three useful properties for knowing where i'm called from for example. — Cristian Batista, Jan 26 '18 at 10:45

score 5 · Accepted Answer · answered Jan 26 '18 at 10:41

According to MDN

An arrow function expression has a shorter syntax than a function expression and does not have its own this, arguments, super, or new.target. These function expressions are best suited for non-method functions, and they cannot be used as constructors.

Why in Fat arrow functions arguments object is undefined

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