5

I execute the following code and I get no errors, and in the output I see the Success! message. Can you please explain this strange behaviour.

public class Main {

    public static void main(String[] args) {
        int р = 0;
        int p = 1;
        if(р == 0 && p == 1) {
            System.out.println("Success!");
        }

    }

You can check the online demo

Youcef LAIDANI
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ziMtyth
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    They don't have the same name. When I try to search for "int p =" on my browser, only the second variable is found. The first one must be using a different character that looks like 'p'. – Eran Jan 28 '18 at 07:24
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    @Erwin did you read the question? The issue is not with `р == 0 && p == 1` evaluated to true. It's about two variables that seem to have the same name. – Eran Jan 28 '18 at 07:26
  • This is all pretty well explained in the Unicode-related answers to the duplicate question. Since you're also looking into situations where seemingly, one variable has two values are the same time, this is the right duplicate as this duplicates looks into how to make a variable appear to be equal to 3 values at the same time, and many of the answers use Unicode to create variables with different names that look the same when they're viewed – Erwin Bolwidt Jan 28 '18 at 07:26
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    When you paste that letter into URL address field, Google suggests some Russian words. – joval Jan 28 '18 at 07:27
  • @Eran Yes Eran - see my explanation above that I was just typing. I've added another duplicate that more explicitly answers the same question. – Erwin Bolwidt Jan 28 '18 at 07:27
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    you can add [ideone demo](https://ideone.com/K1qJcX) to your question to make it clear – Youcef LAIDANI Jan 28 '18 at 09:52
  • @YCF_L It would be nice of you if you can make an edit to the question =) – ziMtyth Jan 28 '18 at 10:42
  • I've seen at least one or two variations of this question in the last few days mmm... – DPM Jan 28 '18 at 12:37
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    @ErwinBolwidt I've checked your post and you talked about using the same variable in multiple tests in the same `if` and you solved it with a multi threading technic, in the other hand my post was about the naming of a variable which turned out to be different `p` according to JonSkeet, do you see any threading in my post? I don't see any correspondance between my post and yours. , I believe that my post is obviously not a duplicate. I demande to reopen it. – ziMtyth Jan 29 '18 at 07:35
  • @ziMtyth I didn't close it as a duplicate (this time) - the fact that it was closed again by someone else is a clear indication that it *is* a duplicate. In fact, the second link has one answer that describes exactly the same situation as in the answer that you accepted below. And for the other duplicate, I didn't refer to the threading answer but to the unicode answers, as I explained above. In any case, if you believe a closure is incorrect or that you have fixed your question, you can click the "reopen" link under your question and nominate it for re-opening. – Erwin Bolwidt Jan 29 '18 at 08:38

1 Answers1

11

both are different variables (but looks similar), you can see the UTF-16 is different

    int р = 0;
    int p = 1;
    if (р == 0 && p == 1) {
        System.out.println("Success!");
        System.out.println("p UTF-16 is " + (int) 'p');
        System.out.println("р UTF-16 is " + (int) 'р');
    }

output

Success!
p UTF-16 is 112
р UTF-16 is 1088
Saravana
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