I have this array:
var arr = [];
var i =
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1) There:
setInterval ( function push(arr) {arr.push(i+1)} , 5*1000)
you're shadowing the arr variable (that is declaring a new variable which hides the external one). You're thus pushing to undefined. There's of course the same problem when you read the values.
2) If you always push i+1 you always push 1. You probably want i++
Simply do
setInterval ( function push() {arr.push(i++)} , 5*1000)
Denys Séguret
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can you please explain what is shadowing? – Nahid Hasan Jan 29 '18 at 17:05
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1@MirthfulNahid It means hiding the external variable by declaring a new local one. Because declaring an argument declares a variable in the scope of the function call. – Denys Séguret Jan 29 '18 at 17:09
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thanks , i wanted i++ – Nahid Hasan Jan 29 '18 at 17:12
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there is one problem, the whole is printed after 2 sec, if static array . how can i give give 2 sec break for each array element – Nahid Hasan Jan 29 '18 at 17:19
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@MirthfulNahid I don't understand this requirement. You want to just print an item and not the whole array? – Denys Séguret Jan 29 '18 at 17:20
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yes i want to print only one element after 2 sec, from the first to last – Nahid Hasan Jan 29 '18 at 17:21
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the just log `arr[arr.length-1]` instead of `arr` – Denys Séguret Jan 29 '18 at 18:00