onActivityResult's intent.getPath() doesn't give me the correct filename

Question

I am trying to fetch a file this way:

final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
    String[] mimetypes = {"application/pdf"};
    chooseFileIntent.setType("*/*");
    chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
    if (chooseFileIntent.resolveActivity(activity
                        .getApplicationContext().getPackageManager()) != null) {
        chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
        activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
    }

Then in onActivityResult :

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
}

According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :

/document/acc=1;doc=28

So what to do? Thanks for your help.

CommonsWare · Accepted Answer · 2019-04-06T14:41:29.293

9

I am trying to fetch a file

Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.

According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()

That was never correct, though it tended to work on older versions of Android.

So what to do?

Well, that depends.

~~If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT.~~ (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)

If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:

If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user

edited Apr 06 '19 at 14:41

answered Jan 29 '18 at 22:05

CommonsWare

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1

Really great and complete answer! Thank you very much, `DocumentFile.fromSingleUri()` did the trick :) – Rob Jan 29 '18 at 22:12
@CommonsWare, How to get the file path using DocumentFile ? – Amila Iddamalgoda Oct 07 '18 at 12:37
1

@Amila You don't. You open an `InputStream` on the content identified by the `Uri` in the `DocumentFile`, and you consume the content that way. – CommonsWare Oct 07 '18 at 12:47
it may not work always ! check my solution:https://stackoverflow.com/a/59104787/3141844 – Criss Nov 29 '19 at 12:28

score 0 · Answer 2 · answered Jan 23 '20 at 01:24

To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.

private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;

private void chooseFile() {
    Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
    fileChooser.setType("application/pdf");
    startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}

@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == FILEPICKER_RESULT_CODE) {
        if (resultCode == RESULT_OK) {
            fileUri = data != null ? data.getData() : null;
            if (fileUri != null) {
                DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
                if (d != null) {
                    Log.d("TAG", "file name: " + d.getName());
                    Log.d("TAG", "file path: " + d.getUri().getPath());
                    sendEmail(fileUri);
                }
            }
        }
    }
}

private void sendEmail(Uri path) {
    String email = "example@gmail.com";
    Intent intent = new Intent(android.content.Intent.ACTION_SEND);
    intent.setType("application/octet-stream");
    intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
    String[] to = { email };
    intent.putExtra(Intent.EXTRA_EMAIL, to);
    intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
    intent.putExtra(Intent.EXTRA_STREAM, path);
    startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}

hope it helps.

onActivityResult's intent.getPath() doesn't give me the correct filename

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