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Why can't you assign a number with a decimal point to the decimal type directly without using type suffix? isn't this kind of number considered a number of type decimal?

decimal bankBalance = 3433.20; // ERROR!
prodev42
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  • Did we all miss the last part of the question or was that just added? – Brian Rasmussen Jan 27 '09 at 21:09
  • The reason, as I and others said, is that there is no implicit type conversion done. If you enter 3433.20, that's a float by default. C# won't convert a float to a decimal. I don't know why they made this decision, but MSDN shows that this is the case. – Eddie Jan 28 '09 at 06:33
  • My answer below has the link http://msdn.microsoft.com/en-us/library/364x0z75(VS.80).aspx to MSDN where they explain this. – Eddie Jan 28 '09 at 06:34

6 Answers6

114

Edit: I may have missed the last part of the question, so the overview below is hardly useful.

Anyway, the reason you can't do what you're trying to do is because there is no implicit conversion between floating point types and decimal. You can however assign it from an integer, as there is an implicit conversion from int to decimal.


You can, but you have to use this syntax (or do an explicit cast to decimal).

decimal bankBalance = 3433.20m;

and for floats it is

float bankBalance = 3433.20f;

default is double

double bankBalance = 3444.20;
Brian Rasmussen
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22

Actually, hidden spec feature: you can ;-p

decimal bankBalance = (decimal)3433.20;

This is genuinely parsed by the compiler as a decimal (not a float and a cast). See the IL to prove it. Note that the precision gets truncated, though (this has 1 decimal digit, not the 2 you get from the M version).

IL generated:

L_0001: ldc.i4 0x861c
L_0006: ldc.i4.0 
L_0007: ldc.i4.0 
L_0008: ldc.i4.0 
L_0009: ldc.i4.1 
L_000a: newobj instance void [mscorlib]System.Decimal::.ctor(int32, int32, int32, bool, uint8)
L_000f: stloc.0 

Compared to:

decimal bankBalance = 3433.20M;

Which generates:

L_0001: ldc.i4 0x53d18
L_0006: ldc.i4.0 
L_0007: ldc.i4.0 
L_0008: ldc.i4.0 
L_0009: ldc.i4.2 
L_000a: newobj instance void [mscorlib]System.Decimal::.ctor(int32, int32, int32, bool, uint8)
L_000f: stloc.0 

The only difference is the decimal digits (1 vs 2, and a factor of 10, accordingly)

Marc Gravell
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7

This

decimal bankBalance = 3433.20M;

will work. The reason is that float and decimal are very different types. float will give you an extremely close approximation of the number you enter, but decimal will give you the exact number. 99% of the time you wont notice the difference, and should just use float.

Matt Briggs
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5

Your answer consists of two important points:

  1. All numerical literals with a decimal point are inferred to be of type double by the C# compiler, consequently, 3433.20 is a double by default.

  2. double numbers do not implicitly convert to decimal because although decimal is more precise than double it covers a shorter range so overflow is possible during a cast from double to decimal.

double's range: ±(~10^−324 to 10^308) with 15 or 16 significant figures.

decimal's range: ±(~10^-28 to 10^28) with 28 or 29 significant figures.

Saeb Amini
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    downvoted, although more information is always helpful, you didn't answer his question – RollRoll Jun 25 '16 at 21:34
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    @ThePoet, the answer to the question is precisely because the type is not considered a decimal, but a double, which has a wider range than decimal and can't be assigned to it implicitly because of possible data loss (it's actually quite unfortunate that the higher answers don't mention this to inform people _why_ you should explicitly include that suffix). Those point are included in the answer so I believe this more than answers the question. – Saeb Amini Jun 26 '16 at 03:51
3

See the MSDN page on decimal which explains that there is no implicit conversion between normal float types and decimal.

Try

decimal bankBalance = 3433.20m;

Eddie
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0

I really like Convert class in many cases. Its very reliable.

decimal bankBalance = Convert.ToDecimal(3433.20);

taipignas
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