How am i suppose to understand this ouput for join ()(using python 3)?

Question

Here is the image,

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Here is what i tried playing with join function but i don't get what's going on here if anyone out there encountered with same then please help me out!.

A string is an *iterable* of strings: 1-char strings that are the characters, so you `join` `HI` between the characters of `'bye'`. — Willem Van Onsem, Jan 31 '18 at 13:46
Pleas don't post screenshots of your code; post the text itself. — chepner, Jan 31 '18 at 13:47
I'm sure you read the [documentation for `join`](https://docs.python.org/3/library/stdtypes.html?highlight=join#str.join), so what part of it do you not understand? — Matthias, Jan 31 '18 at 13:47
hey yo'll i'am new to stack overflow and programming , ik that was dumb question and dumb way of asking as well.Thanks though. — saransh thukral, Jan 31 '18 at 14:21

Sam Rockett · Answer 1 · 2018-01-31T14:00:26.107

2

Strings can be iterated through, and when you do iterate through one, it will spin through each individual letter.

str.join(iterable) will join the iterable inside the brackets together using the string outside the brackets.

If the iterable was a list, it'd be easy to see what is going on

>>> l = ["Alice", "Ben", "Casey"]
>>> ", ".join(l)
"Alice, Ben, Casey"

And with a string,

>>> "-".join("Hello!")
>>> # Same as "-".join(["H", "e", "l", "l", "o", "!"])
"H-e-l-l-o-!"

edited Jan 31 '18 at 14:00

answered Jan 31 '18 at 13:53

Sam Rockett

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The string isn't casted into an iterable, a string _is_ an iterable. – Matthias Jan 31 '18 at 13:56
Good catch, I've edited the post. – Sam Rockett Jan 31 '18 at 14:01

score 0 · Answer 2 · answered Jan 31 '18 at 13:48

String is a sequence of characters. Join function concatenates the sequence (iterable) to a new string by joining them on the string you called the function on. In this case it's s with value of 'HI'.

Its not different than:

print(" ".join("hello", "world"))

That results in "hello world".

score 0 · Answer 3 · answered Jan 31 '18 at 13:50

The thing is, string.join receives a iterable as a parameter, so the string you are passing it, will be treated as a iterable and not a string, so you will do b, joined with y joined with e. If you do s.join(['bye']), then the output will be the one I assume you were expecting

How am i suppose to understand this ouput for join ()(using python 3)?

3 Answers3