Get IP address from python

Question

I'm trying to get the ip address associated with network interface without spawning additional processes in Linux:

def get_ip_address(ifname):
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    return socket.inet_ntoa(fcntl.ioctl(
        s.fileno(), 0x8915,  # SIOCGIFADDR
        struct.pack('256s', ifname[:15].encode('utf-8'))
        )[20:24])

But always getting this error:

struct.pack('256s', ifname[:15].encode('utf-8'))
OSError: [Errno 99] Cannot assign requested address

How can I solve this?

I get this error message when my interface is not assigned an IP address. which interface do you test and what does `/sbin/ifconfig -a` report ? — Gilles Gouaillardet, Feb 05 '18 at 00:32

score 3 · Answer 1 · answered Feb 04 '18 at 14:35

3

Translate host to ip :

import socket
print (socket.gethostbyname(socket.gethostname()))

To get host by name :

import socket
print (socket.gethostbyname("www.goole.com"))

answered Feb 04 '18 at 14:35

An0n

705
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1

And what if I have multiple network interfaces without any internet connection? – lichb0rn Feb 04 '18 at 18:49
1

the first comment returns `127.0.0.1` .... – Ricky Levi Mar 14 '19 at 19:03
It always returns the output as '127.0.0.1'. But I need both public and private IP addresses. – Mohith7548 Mar 30 '19 at 17:29
Do you have a working internet connection? – An0n Mar 30 '19 at 20:11

Get IP address from python

1 Answers1