When I run my program, it gave an error as usual. When I looked back at the code, I found the error a bit strange. I put print in the code to analyze a variable and I saw something that was total nonsense. Somehow a variable lost a value but in the code it doesn't change! I will share a sample code but same story here:
def f(a):
a.remove(1)
return a
list1 = [1, 2, 3]
print(f(list1))
print(list1)
in the first print you would expect an output as:
[2,3]
and in second print you would expect:
[1,2,3]
as it didn't change in the main code. Well it turns out the output is like this:
[2, 3] [2, 3]
In my program, I went nuts trying to solve it. I debugged it and I saw that the variable changes in a function similar to f(). I thought that since in a function the program would run in scope level, it wouldn't influence a global variable like list1. So is this a bug in python or should I avoid using methods in functions?
By the way, I solved the problem by editing like:
def f(a):
x = list(a)
x.remove(1)
return x
list1 = [1,2,3]
print(f(list1))
print(list1)
for some reason x=a wasn't enough so I used x=list(a)
