"java.lang.UnsupportedOperationException: Not supported yet."

Question

What I am trying to do :

I am trying to connect to Web Portal [that uses https]using Java. I have written code for supplying user credentials using Authenticator class.When I run the program I get an Exception:

"java.lang.UnsupportedOperationException: Not supported yet"

I have the code posted :

public class Main {

    public class MyAuthenticator extends Authenticator {

        protected PasswordAuthentication getpasswordAuthentication() {
            String username = "username";
            String password = "password";
            // Return the information
            return new PasswordAuthentication(username, password.toCharArray());
        }

        @Override
        public Result authenticate(HttpExchange he) {
            throw new UnsupportedOperationException("Not supported yet.");
        }
    }

    public static void main(String[] args) {
        // TODO code application logic here


        TrustManager[] trustClients = new TrustManager[]{
            new X509TrustManager() {

                public void checkClientTrusted(X509Certificate[] xcs, String string) throws CertificateException {
                    throw new UnsupportedOperationException("Not supported yet.");
                }

                public void checkServerTrusted(X509Certificate[] xcs, String string) throws CertificateException {

                    throw new UnsupportedOperationException("Not supported yet.");
                }

                public X509Certificate[] getAcceptedIssuers() {
                    return null;
                    //throw new UnsupportedOperationException("Not supported yet.");
                }
            }
        };
        try {
            SSLContext sslcontext = SSLContext.getInstance("SSL");
            sslcontext.init(null, trustClients, new java.security.SecureRandom());
            HttpsURLConnection.setDefaultSSLSocketFactory(sslcontext.getSocketFactory());

        } catch (Exception e) {
            System.out.println("in 1st catch " + e);
        }


        try {
            URL url = new URL("https://someURL.server.com/fmk/jsp/ltpaLogin.jsp");
            URLConnection urlconnection = url.openConnection();
            System.out.println(urlconnection);
            System.out.print(urlconnection.getInputStream().toString());



} catch (Exception e) {
            System.out.println("in 2ndcatch " + e.getMessage());
        }
    }
}

the exception "java.lang.UnsupportedOperationException: Not supported yet"is raised in the 2nd Try.Is my approach correct ? if not is there any alternative to do so ?

When I open the page in web browser I get the login page;Once I supply my credentials the web portal is displayed

Can any one please suggest how to hit the webportal and supply my credentials and check the authentication is success or not ? Any sample code snippets will be really helpful Thanks in advance..

Related: [*Is there anything like .NET's NotImplementedException in Java?*](https://stackoverflow.com/q/2329358/642706) — Basil Bourque, Feb 23 '19 at 03:01

score 11 · Accepted Answer · answered Feb 01 '11 at 10:25

11

Have you seen this code fragment ?

    @Override
    public Result authenticate(HttpExchange he) {
        throw new UnsupportedOperationException("Not supported yet.");
    }

It's precisely the one that will throw the aforementionned exception each time you try to authenticate.

So, to my mind, the solution to your authentication problem is quite simple : implement this method.

answered Feb 01 '11 at 10:25

Riduidel

22,052
14
85
185

OOppss !! This was generated by Netbeans ! I dint notice this !! I will implement this and try Thanks a lot. – ManiVI Feb 03 '11 at 16:25

score 9 · Answer 2 · answered Feb 01 '11 at 10:28

9

if you don't want implement this method :

    @Override
    public Result authenticate(HttpExchange he) {
        throw new UnsupportedOperationException("Not supported yet.");
    }

take it easy , only delete this line of method :

throw new UnsupportedOperationException("Not supported yet.");

answered Feb 01 '11 at 10:28

mehdi shahdoost

1,469
5
17
27

2

Deleting the line will result in compile-time errors. You need to at least add a `return null;`. – Ingo Bürk Oct 19 '13 at 21:43
ya!~ Auto generated by Android Studio when writing onReceiver(). – Kyung Lee Mar 11 '17 at 13:17

score 4 · Answer 3 · answered Feb 01 '11 at 10:32

You've probably used an IDE such as Netbeans to implement an interface / override an abstract class that needs certain methods implementing. When IDEs do this (Netbeans definitely does) they generate method stubs for you like this so the code still compiles but if you try and call a method you haven't actually implemented you get an unavoidable error.

Usually this means you have to implement the given method, but sometimes an implementation does genuinely call for a blank method stub, in which case just delete the line that's throwing the exception.

Yes I have used Netbeans for writing the code and netbeans gave me the suggestions for generating the Stubs Thanks for the Tip !! — ManiVI, Feb 03 '11 at 16:28

score 0 · Answer 4 · answered Dec 23 '13 at 04:15

0

This happens when you did not provide implementations for all methods from the interface you've implemented. Check which method you not implemented.

answered Dec 23 '13 at 04:15

KM_Saravanan

33
7

score 0 · Answer 5 · edited Apr 05 '20 at 10:46

0

You don't give a body to your method. Check the line where you have the problem and override your method with the code you want.

edited Apr 05 '20 at 10:46

Mark Tielemans

1,528
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answered Apr 05 '20 at 03:04

bart-khalid

198
1
9

"java.lang.UnsupportedOperationException: Not supported yet."

5 Answers5

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