unexpected end in my code

Question

Hi i'm having problem with my website i'm getting synttax error , unexpected end in file .. in line 40 ()
what should i do to solve this problem ?

<?php
$dbc = mysqli_connect();
if( isset($_POST['message1']) && isset($_POST['message2']) && isset($_POST['message3']) )


{ 

                        $message1 = $_POST['message1'];
                        $message2 = $_POST['message2'];
                        $message3 = $_POST['message3'];

    $query = "INSERT INTO textarea (message1,message2,message3) VALUES ('$message1','$message2','$message3')";

if(mysqli_query($dbc,$query))
{echo "Thanks for your opinoin";}
?>

<!DOCETYPE html>
<html>
<head>
<style>

body {

    text-align:center;
padding-top:300px;
font-size:40px;
color:white;
font-style:oblique;

}


</style>
</head>

<body background="hero.jpg" >

    </body>
    </html>

i dont see any problem with my code and i'm getting that problem how should i do to solve it becuase it says in line 40 and line 40 is the end of the html please help

and remove your username etc. from the second line of your post.. — JeroenE, Feb 07 '18 at 10:07
BTW you have `<!DOCETYPE html>` instead of ` ` and you **shouldn't** print **anything** before the DOCTYPE annotation. — flx, Feb 07 '18 at 10:07

score 3 · Answer 1 · edited Feb 07 '18 at 10:15

3

You Need to Close your first if statement }. Like this :

<?php
$dbc = mysqli_connect();
if( isset($_POST['message1']) && isset($_POST['message2']) && isset($_POST['message3']) )
{ 

    $message1 = $_POST['message1'];
    $message2 = $_POST['message2'];
    $message3 = $_POST['message3'];

    $query = "INSERT INTO textarea (message1,message2,message3) VALUES ('$message1','$message2','$message3')";

    if(mysqli_query($dbc,$query)){
        echo "Thanks for your opinoin";
    }
}
?>

edited Feb 07 '18 at 10:15

Ahmad Saidan

3
3

answered Feb 07 '18 at 09:59

Nawin

1,653
2
14
23

Thank you guys the problem is sloved . – Ahmad Saidan Feb 07 '18 at 10:11

unexpected end in my code

1 Answers1