JAVA: ANDROID: Word index of string

Question

public void searchSong(String songToSearch){
    Toast.makeText(getApplicationContext(), songToSearch, Toast.LENGTH_SHORT).show();
    boolean found = false;
    for(int i = 0; i < fileArray.length; i++ ){
        String value = fileArray[i].toLowerCase().replace(".mp3","");
        if (songToSearch.toLowerCase().matches(value) && !found) {
            Toast.makeText(getApplicationContext(), value, Toast.LENGTH_SHORT).show();
            found = true;
        } else {
            found = false;
        }
        if(found){
            Toast.makeText(getApplicationContext(), "Found", Toast.LENGTH_SHORT).show();
        }
    }
}

I want to use the code to check if the songToSearch is a part of any string inside the fileArray Example lets say that fileArray[2] is equal to "Hello world" and the songToSearch is equal to "world" I would like to make the boolean found true... However this is not happening... the boolean never changes

you basically want search functionality for your songs list ? If yes you should try implementing search view. — Vivek Mishra, Feb 08 '18 at 13:02
use `value.toLowerCase().contains(songToSearch.toLowerCase())` instead of `matches` — XtremeBaumer, Feb 08 '18 at 13:03
the boolean changes, but it also changes back on the next value which doesn't contain the word. do you want to show multiple results or just the first? — XtremeBaumer, Feb 08 '18 at 15:25
@XtremeBaumer Wait... does not the && in the if stop the loop? — DrunkProgrammer, Feb 08 '18 at 15:51
@DrunkProgrammer it does not : it stops checking the conditions if the first element is false. It's not a break statement. e.g. `if ((s != null) && (s.contains("bar"))){}` will not try to check if bar is contained in "s" if s is null — Sirmyself, Feb 08 '18 at 15:58

score 0 · Answer 1 · answered Feb 08 '18 at 13:04

0

see docs: https://docs.oracle.com/javase/7/docs/api/java/lang/String.html

public boolean  matches(String regex)

Tells whether or not this string matches the given regular expression.

you need:

public boolean contains(CharSequence s)

answered Feb 08 '18 at 13:04

LunaVulpo

3,043
5
30
58

score 0 · Answer 2 · answered Feb 08 '18 at 16:04

0

            if (Pattern.compile(Pattern.quote(songToSearch), Pattern.CASE_INSENSITIVE).matcher(value).find()) {
            playMusic(songToSearch);
        }

Would solve the problem... My post was actually a duplicate

answered Feb 08 '18 at 16:04

DrunkProgrammer

3
7

JAVA: ANDROID: Word index of string

2 Answers2