sorting a list of strings as they are integers

Question

I have a simple question of sorting lists based on values. I want to order a list of strings as they are integers, and consider for sorting just the characters that are starting on second position.

As an example, I have this list:

L = ['X102', 'X201', 'X805', 'X111', 'X032', 'X155', 'X0123', 'X1113', 'X881', 'X1022']

if I sort it using sorted(L) I get:

['X0123', 'X032', 'X102', 'X1022', 'X111', 'X1113', 'X155', 'X201', 'X805', 'X881']

My struggle is to sort the list just considering the "integers", so just the numbers are after 'X' in order that the result to look like this:

SORTED_L = ['X032', 'X102', 'X111', 'X0123', 'X155', 'X201', 'X805', 'X881', 'X1022', 'X1113']

`sorted(L, key= lambda x: int(x[1:]))` – Chris_Rands Feb 08 '18 at 16:37 — Chris_Rands, Feb 08 '18 at 16:37
Someone find a dupe please – Chris_Rands Feb 08 '18 at 16:37 — Chris_Rands, Feb 08 '18 at 16:37
thanks - that answered my question – alc Feb 08 '18 at 16:47 — alc, Feb 08 '18 at 16:47

pault · Answer 1 · 2018-02-08T16:44:14.823

3

You can specify a custom sort key using a lambda function:

SORTED_L = sorted(L, key=lambda x: int(x.replace('X', ''))

In this case, for each value in L, the lambda will remove the 'X' and convert to an int.

edited Feb 08 '18 at 16:44

answered Feb 08 '18 at 16:38

pault

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sorting a list of strings as they are integers

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