Javascript match on third type of string

Question

I am trying to extract a version and need to match on a third variant as shown here:

ersion ([^,]*)(,)? RELEASE

Need to match on:

Version 03.06.07b.E, RELEASE SOFTWARE (fc1)
Version 03.06.07b.E RELEASE SOFTWARE (fc1)
version 1.3(2)ES3

Match fails on the third row.

How about `ersion (?:([^,]*)(,)? RELEASE|.*)`? Your question is i poor shape since it is not clear what is allowed/not allowed for the 3rd match. It is not well specified. — Micha Wiedenmann, Feb 09 '18 at 08:19
Possible duplicate of [Learning Regular Expressions](https://stackoverflow.com/questions/4736/learning-regular-expressions) — Biffen, Feb 09 '18 at 08:20
Try [`/Version ([^,]*)(?:,? RELEASE)?/i`](https://regex101.com/r/rAnhMq/1), but it seems you do not even need `(?:,? RELEASE)?` if you want to extract just what `([^,]*)` captures. [`/Version\s+([^,\s]*)/i`](https://regex101.com/r/rAnhMq/2) might be all you need. — Wiktor Stribiżew, Feb 09 '18 at 08:20
Also: "Version 03.06.07b.E RELEASE SOFTWARE (fc1) RELEASE" will match your regex". — Micha Wiedenmann, Feb 09 '18 at 08:22

score 2 · Accepted Answer · answered Feb 09 '18 at 11:53

The third string is not matched because it does not contain the required RELEASE substring.

It seems all you need to match is any 0+ chars other than whitespace before the , char and after Version substring.

Use

/Version\s+([^,\s]*)/i
(?i)Version\s+([^,\s]*)

See the regex demo.

The Version will match version, too, due to the case insensitive flag, \s+ matches 1+ whitespaces and ([^,\s]*) will capture 1 or more chars other than whitespace and ,.

Javascript match on third type of string

1 Answers1