How to set bit and print all bits in number using C

Asked Feb 11 '18 at 10:36

Active Feb 11 '18 at 11:01

Viewed 980 times

I have following function to print bits:

void printBits(unsigned int num)
{
   for(int bit=0;bit<(sizeof(unsigned int) * 8); bit++)
   {
      printf("%i ", num & 0x01);
      num = num >> 1;
   }
}

and I want to set bit number 5 as follow:

unsigned int DataInMemory = 0x00000000;
DataInMemory |= (1<<5);

the result of printBites function is:

0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

it means that 1 << 5 set bit 6 not bit 5. Is it difference between bit position (indexes) and bit in programming nomenclature? How to set bit and print all bits in number using C?

edited Feb 11 '18 at 10:40

asked Feb 11 '18 at 10:36

ElConrado

1,477
4
20
46

2

It did set bit no. 5 (i.e.: the 6th bit). Bit indices start counting at 0, not 1. – JFMR Feb 11 '18 at 10:39
Anybody who thinks this can be kept open let me know. Will open it. – user2736738 Feb 11 '18 at 10:42
@ElConrado.: Those duplicates help you? Is it ok? – user2736738 Feb 11 '18 at 10:45
1

@水飲み鳥 comment is useful. It's ok. – ElConrado Feb 11 '18 at 10:47
@coderredoc OP's problem is actually (implicitly) explained [here](https://stackoverflow.com/questions/26004263/set-the-i-th-bit-to-zero?noredirect=1&lq=1), not in the answers, but actually in the question itself. Could you please consider to add that post to the list? – JFMR Feb 11 '18 at 11:00
1

@水飲み鳥.: Added.. – user2736738 Feb 11 '18 at 11:03

How to set bit and print all bits in number using C

0 Answers0