Python yes/no def

Question

I'm using the example below:

APT command line interface-like yes/no input?

I want to make it its own definition as outlined then call it upon demand, like this:

def log_manager():  
    question = "Do you wish to continue?"  
    choice = query_yes_no_quit(question, default="yes")  
        if choice == 'y':  
            print ("you entered y")  
        else:     
            print ("not working")

Regardless of what I input, "not working" is always printed. Any guidance would be really appreciated!

What is the return value, `choice`, from the `query_yes_no_quit()` function? Please print that and **update** your question. — S.Lott, Feb 02 '11 at 23:42

score 9 · Accepted Answer · answered Feb 02 '11 at 22:36

9

The function returns True/False. So use if choice:

Btw, you could have easily found out the solution on your own by adding print choice ;)

answered Feb 02 '11 at 22:36

ThiefMaster

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Thanks for that! I sorted it out based on your answer. Thanks! – Publiccert Feb 02 '11 at 23:40

score 1 · Answer 2 · edited May 20 '15 at 11:20

1

Use:

if choice:
    print("you entered y")
else:
    print("not working")

the function returns True / False, not "y" / "n".

edited May 20 '15 at 11:20

meshy

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answered Feb 02 '11 at 22:37

max

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Python yes/no def

2 Answers2