I happened to work on the similar issue. My python script load .so library to get an image buffer address from c++ .so. After I got the buffer address, I need to be able to read each byte in the buffer. I used "from_address" to create a list object:
imageBytes = list(c_ubyte * dataSize).from_address(pointer)
The following shows the details how to get memory address passed from c++ to pyth and how to access the memory data on python side too. In c++ code frameprovider.cpp:
dataPackPtr = new DataPack();
DataPack * getFrame(){
uint32_t width = 1920;
uint32_t height = 1208;
const size_t buffersize = width * height * 4;//rgba, each color is one byte
unsigned char* rgbaImage = (unsigned char * )malloc(buffersize);
memset(rgbaImage, 0, buffersize); // set all the buffer data to 0.
dataPackPtr->width = width;
dataPackPtr->height = height;
dataPackPtr->buffersize = buffersize;
dataPackPtr->bufferPtr = rgbaImage;
return dataPackPtr;
}
extern "C" {
DataPack* getFrame_wrapper(){
return getFrame();
}
}
My python:
import ctypes
import binascii
lib = ctypes.cdll.LoadLibrary('/libpath/frameprovider.so')
print vars(lib)
class dataPack(ctypes.Structure):
_fields_ = [("width",ctypes.c_int),
("height",ctypes.c_int),
("buffersize",ctypes.c_int),
("bufferAddress", ctypes.c_void_p)]
lib.getFrame_wrapper.restype = ctypes.POINTER(dataPack)
data = lib.getFrame_wrapper()
print "in python the w= ", data.contents.width, "h=",data.contents.height
print "the buffersize=",data.contents.height
imageBytes = list(
(data.contents.buffersize * ctypes.c_ubyte).
from_address(data.contents.bufferAddress))
print "the len of imageBytes are ", len(imageBytes)
print imageBytes[data.contents.buffersize -1] #print the last byte in the buffer
print "in python, the hex value of element 12 is ", hex(imageBytes[12])