How to get substring after a whitespace?

Question

x.substr(x.find(":") + 1);

How can I do the same, but with whitespace ? because find() ignores spaces.

@Vettel: "*`find()` ignores spaces*" - no, it doesn't. `x.substr(x.find(" ") + 1);` works just fine. Also `x.find(' ')` works, too — Remy Lebeau, Feb 15 '18 at 20:37
The `find` member function does **not** ignore the whitespace. — Ron, Feb 15 '18 at 20:38
@MayankJain: "*Stringstream let you specify delimiters*" - no, it doesn't. You might be thinking of `std::getline()` instead, which has an optional delimiter, and can use a stringstream as input. — Remy Lebeau, Feb 15 '18 at 20:39
You should take a look [here](https://stackoverflow.com/questions/15475744/string-find-is-not-finding-spaces) — Eugene Sh., Feb 15 '18 at 20:40
@vettelsebastian why dont you just try it and see what happens? find(" ") — AndersK, Feb 15 '18 at 20:41
@EugeneSh.: the problem with that question is that the user wasn't reading strings with spaces in them to begin with. That was a problem with using `cin >> ...` to read strings, not with using `find()` to find space characters. — Remy Lebeau, Feb 15 '18 at 20:41
@RemyLebeau Yes. So I would imagine the OP has a similar problem. — Eugene Sh., Feb 15 '18 at 20:42

amar_1995 · Accepted Answer · 2018-02-15T22:29:41.543

4

If you want white space you need to use find_if() with an appropriate lambda that calls is::space()

auto pos = find_if(std::begin(x), std::end(x), [](unsigned char c){return std::isspace(c);});
pos++;
for(;pos!=x.end();pos++)
cout << *pos;

edited Feb 15 '18 at 22:29

answered Feb 15 '18 at 20:42

amar_1995

Please clarify yourself. Which other character? `Ascii` value of `whitespace` is 32 – amar_1995 Feb 15 '18 at 21:15
1

That is the character space. ASCII 32. "White Space" is a couple of other characters including tab. See the defintion of `isSpace()` http://en.cppreference.com/w/cpp/string/byte/isspace – Martin York Feb 15 '18 at 21:16
Ooo, Thanks now i undersand. – amar_1995 Feb 15 '18 at 21:18
Thanks but it gives me error to "pos" in the substr function : https://imgur.com/a/guuDP – Vettel.Sebastian Feb 15 '18 at 22:09
pos is `string::iterator` – amar_1995 Feb 15 '18 at 22:30

1 Answers1