Can someone help me to find why there's no output?

Question

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main(void) {
   char str[50];
   int count[26] = {0};
   int x;
   int len;
   int max;

printf("Enter your input: ");
scanf("%s", str);

while( ! feof(stdin)) {
  len = strlen(str);
  for(x = 0; x < len; ++x) {
    char ch = str[x];
    int sub = ch - 97;
    count[sub] = count[sub] + 1;
  }
  scanf("%s", str);
}
max = count[0];
for(x = 0; x < len; ++x) {
    if(count[x] > max){
      max = count[x];
    }
}

printf("Missing letters: ");
for(x = 0; x < 26; ++x) {
  if(count[x] == 0) {
    x = x + 97;
    printf("%c", x);
  }
}
printf("\n");
return 0;
}

I'm new to C and I've been trying to fix this for a few hours now and I'm just not understanding. I think the issue is with the while loop, but I've just started coding I have no idea. Does anything jump out at anyone? This is supposed to read a sentence and output the letters that were not seen. Thank you.

Aside: please see [Why is `while ( !feof (file) )` always wrong?](http://stackoverflow.com/questions/5431941/why-is-while-feof-file-always-wrong) — Weather Vane, Feb 16 '18 at 22:53
Thank you, Weather. I actually just took the while loop out completely and it works perfectly! — Zach, Feb 16 '18 at 23:14
Usually its a good idea not to remove your question after getting an answer so that others may stumble upon your question and find the answer too — spectacularbob, Feb 16 '18 at 23:16
@spectacularbob: that was not "removing", that was vandalizing. — Jongware, Feb 16 '18 at 23:24

score 0 · Answer 1 · answered Feb 16 '18 at 23:16

0

Your while loop only terminates when there is an EOF. Use Ctrl^D to send the EOF signal to escape the feof function.

answered Feb 16 '18 at 23:16

Ajao Jumat

7
2

Can someone help me to find why there's no output?

1 Answers1