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What I guessed is that in p[-i] it takes the ith position from current pointing one towards the left-hand side.I am just a beginner so is there something more to it. 

     #include<stdio.h>
     int main() {
     int arr[ ]={0,1,2,3,4};
     int *p,i;mm
        for(p=arr+4, i=0;i<=4;i++)
            printf("%d" , p[-i]);//43210
      }
user7264552
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1 Answers1

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p is the pointer to the end of array. So p-i is the pointer to the ith position in the array to the left of p. This p[-i] is the element at that position.

Kaveh Vahedipour
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