46

Can you load a drawable from a sub directory in the assets (not the drawable folder) folder?

Octavian Helm
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Jamie
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8 Answers8

107

Hope this help:

Drawable d = Drawable.createFromStream(getAssets().open("Cloths/btn_no.png"), null);
Rubycon
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    Just wonder, is the file automically closed for you? For safety, I am currently give a variable the return of open(), then close it manually. – Luke Vo Jun 26 '13 at 19:38
  • @DatVM no it doesn't automatically close the inputstream. I have created a class with static method to get the drawable from assets and added it as separate answer down below. – Bart Burg Nov 04 '15 at 13:23
  • @СергейГрушин for vector drawable please use VectorDrawableCompat.createFromStream(context.assets.open("Cloths/btn_no.xml"), null) – Arsenius Mar 26 '19 at 08:29
8

I recommend to use this

 Drawable.createFromResourceStream(resources,new TypedValue(), resources.getAssets().open(filename), null)

which returns properly scaled drawable thanks to resources ...

David
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7

Here's a class with static method to get the drawable from the assets. It also closes the inputstream.

import android.content.Context;
import android.graphics.drawable.Drawable;

import java.io.IOException;
import java.io.InputStream;

/**
 * Created by bartburg on 4-11-2015.
 */
public class AssetsReader {

    public static Drawable getDrawableFromAssets(Context context, String url){
        Drawable drawable = null;
        InputStream inputStream = null;
        try {
            inputStream = context.getAssets().open(url);
            drawable = Drawable.createFromStream(inputStream, null);
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if(inputStream != null) {
                try {
                    inputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
        return drawable;
    }
}
Bart Burg
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2

Here is function that does this for you.

Check the returned Drawable variable for null as null may return if the path is invalid or there is an IOException.

public static Drawable getDrawableFromAssetFolder(String fullPath, Activity ctx) {
    Drawable d =null;
    try {
        d = Drawable.createFromStream(ctx.getAssets().open(fullPath), null);
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return d;
}
spenibus
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Sam J
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2

Yes you can create a Drawable object from an InputStream using the createFromStream() method.

Octavian Helm
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1

I was working in a RecyclerView adapter and found that David's answer was not working for me, (for some reason asset.open remained Unresolved no matter what I imported )

so I found this to work for me (Kotlin code)

val d = Drawable.createFromStream(context?.assets?.open("imageData/${imageName}.png"), null)

here is my directory, as you can see the assets start from the assets folder and here is a link on how to create that assets folder

enter image description here

DarkPh03n1X
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0

This helped getting the right density

private Drawable drawableFromAssetFilename(String filename) {
    AssetManager assetManager = mApplicationContext.getAssets();
    InputStream inputStream = null;
    try {
        inputStream = assetManager.open(filename);
    } catch (IOException e) {
        e.printStackTrace();
    }
    Bitmap bitmap = BitmapFactory.decodeStream(inputStream);

    BitmapDrawable drawable = new BitmapDrawable(mApplicationContext.getResources(), bitmap);
    return drawable;
}
richy
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-1

At this version you can't, if you make a sub folder within your drawable folder you can't use it in your xml file, it won't be recognized when you use android:src.

Take a look at this thread: Can the Android drawable directory contain subdirectories?

Community
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SterAllures
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