How to check if string contains particular characters

Question

str1.toLowerCase().contains(str2.toLowerCase())

works except it returns true for "11 contains 1" but I want it to search for 1 and not 11 or 213 or any occurrence of 1 but just 1 alone

split by space or new line and check result array contains your particular characters? — Surely, Feb 18 '18 at 12:05
Way too broad/unclear. Try researching https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html for example. — GhostCat, Feb 18 '18 at 12:13

score 0 · Answer 1 · edited Feb 18 '18 at 13:26

0

You can loop through your string and do something like this:

for (int i = 0; i < str.length; i++)
{
   if (str[i] == 'your character')
   // your code ...
}

edited Feb 18 '18 at 13:26

Mohammad Usman

37,952
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answered Feb 18 '18 at 12:03

Amity

1

Very inefficient. Regexes will perform way better. – Phantômaxx Feb 18 '18 at 12:19
1

I agree with you ;) ! +1 – Amity Feb 18 '18 at 12:57
How does that apply here. if(liked.toLowerCase()contains(userid)){button1.setTextColor(c.get resources().getColor(R.color.color accent));} – Vine Feb 19 '18 at 18:21

score 0 · Answer 2 · answered Feb 18 '18 at 12:22

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MyClass {
    public static void main(String args[]) {
        String s = "fsdhfh11sdfsjad";
        Pattern patternOne = Pattern.compile("(.)*(1)(.)*");
        Pattern patternOneOne = Pattern.compile("(.)*(11)(.)*");

        Matcher matchOne = patternOne.matcher(s);
        Matcher matchOneOne = patternOneOne.matcher(s);

        if(matchOne.find() && !matchOneOne.find()){
            System.out.println("Yes");
        }

    }
}

You can test your String with regex like these. This works for me. I hope it could help you. :)

Greethings

Noixes

How to check if string contains particular characters

2 Answers2