How can i take the 0.5 of the folder name?

Asked Feb 21 '18 at 13:15

Active Feb 21 '18 at 13:15

Viewed 46 times

My folder name is : east_resized_0.5 what i want is, if i see the specific word resized in the name to take the number after, the number being any in this case 0.5, could be 7.23 etc..

what i have done is :

path_to_east = 'data/east_resized_0.5'
resized = re.findall(r'resized',path_to_east)
if resized:
    numbers = re.findall(r'\d+', path_to_east)
    print(numbers)
    resized = numbers[0] +'.'+ numbers [1]
    print(resized)

The output will be

['0', '5']
0.5

which does give me what i want eventually but it's not a clean way to say the least and it'll get even messier when i have to make a while loop to make sure every element is in resized if for example the number is 7.23. How can i use regex to make my code cleaner and more efficient

asked Feb 21 '18 at 13:15

Allen

1

Use `m = re.search(r'resized_(\d+(?:\.\d+)?)',path_to_east)` and `if m: print(m.group(1))` – Wiktor Stribiżew Feb 21 '18 at 13:20
1

How about not use regex and simply: `r = s.split('resized_')[1:]`. If r exists... `return r[0]`. – Anton vBR Feb 21 '18 at 13:20
@WiktorStribiżew works, wish it wasn't marked as duplicate to be able to accept in bellow. – Allen Feb 21 '18 at 13:23
Matching numbers is a very well-known issue. If I answer, a lot of people will downvote both your question and my answer. – Wiktor Stribiżew Feb 21 '18 at 13:24

How can i take the 0.5 of the folder name?

0 Answers0