I am looking to write code that takes an input and looks for y or n. I am having a problem filtering out things that are not y or n and if the input is incorrect, that it goes and asks for the input again.
Here are a couple things I've tried:
while True:
try:
need_a_classlist = int(input("\nDo we need to make a classlist first? Y/N "))
except ValueError or str(need_a_classlist).lower != ("y", "n"):
print("\nOkay, let's make a classlist!")
break
else:
print("\nInvalid Response, please type 'y' or 'n'.")
continue
and:
if need_a_classlist == "y":
def add_new_student(student):
class_list.append(student)
return class_list
#get a number for a classlist
number_of_students = int(input("\nHow many students in the class? "))
#user input to add to class list
while number_of_students > 0:
new_student_name = input("\nWhat is the students name? ").lower()
if new_student_name.isalpha():
add_new_student(new_student_name)
print( "\n" + new_student_name.title() + " added to class list!")
number_of_students -= 1
if number_of_students == 0:
break
#If they say no
elif need_a_classlist == "n":
print("\nOkay let's move on to the seating chart.")
#If they put in something else
else:
print("\nInvalid entry, please try again.")
but this does not repeat.