Formatting a JSONArray in Java

Question

So I'm building a recipe app. I want to show the ingredients in a list in a TextView object for now.

The code below is how I'm doing it at the moment. The ingredients (in ingredientLines) is just put into a string.

JSONObject obj = new JSONObject(response);
JSONArray hits = obj.getJSONArray("hits");
for (int i = 0; i < hits.length(); i++) {
    JSONObject a = hits.getJSONObject(i);
    JSONObject recipe = a.getJSONObject("recipe");
    ListItem item = new ListItem(
        recipe.getString("label"),
        recipe.getString("source"),
        recipe.getString("image"),
        recipe.getString("ingredientLines"),
        recipe.getString("url")
    );
}

This is how the string looks now

"ingredientLines" : [ "1 pound multigrain spaghetti (recommended: Barilla Plus)", "Kosher salt", "2 teaspoons black peppercorns", "3 tablespoons unsalted butter", "1 cup coarsely grated Pecorino Romano cheese", "2 full handfuls baby arugula, roughly chopped" ]

I want it to look like

"1 pound multigrain spaghetti (recommended: Barilla Plus)\n Kosher..."

This is the JSON that I am parsing from

"recipe" : {
    "uri" : "http://www.edamam.com/ontologies/edamam.owl#recipe_7a38f039e2a9d3df25e65cc64bc0f87d",
    "label" : "The Secret Ingredient (Black Pepper): Multigrain Cacio e Pepe with Arugula Recipe",
    "image" : "https://www.edamam.com/web-img/f59/f59ec1a536535e9072bbf9a7c2432779.jpg",
    "source" : "Serious Eats",
    "url" : "http://www.seriouseats.com/recipes/2011/02/the-secret-ingredient-black-pepper-multigrain-cacio-e-pepe.html",
    "shareAs" : "http://www.edamam.com/recipe/the-secret-ingredient-black-pepper-multigrain-cacio-e-pepe-with-arugula-recipe-7a38f039e2a9d3df25e65cc64bc0f87d/pep",
    "yield" : 4.0,
    "dietLabels" : [ "Balanced" ],
    "healthLabels" : [ "Sugar-Conscious", "Vegetarian", "Peanut-Free", "Tree-Nut-Free", "Alcohol-Free" ],
    "cautions" : [ ],
    "tags" : [ "pasta", "pepper", "The Secret Ingredient", "vegetarian" ],
    "ingredientLines" : [ "1 pound multigrain spaghetti (recommended: Barilla Plus)", "Kosher salt", "2 teaspoons black peppercorns", "3 tablespoons unsalted butter", "1 cup coarsely grated Pecorino Romano cheese", "2 full handfuls baby arugula, roughly chopped" ]
}

How are you setting your textview value? (provide the code please) — Rafael Paulino, Feb 21 '18 at 20:01
@RafaelPaulino It's being put in a recycler view. I added the code though I'm fine with setting the text I just want to know how to format it. — Joe Tobin, Feb 21 '18 at 20:04
Can you extend your json example with the whole response json you get, not only the Recipe part? — pirho, Feb 22 '18 at 20:26

Rafael Paulino · Answer 1 · 2018-02-21T20:08:15.723

0

Use String.join("\n", ingredientLines) to transform the array in a string with "\n" between the items.

So, instead of recipe.getString("ingredientLines") use:

String.join("\n", recipe.getJSONArray("ingredientLines"))

edited Feb 21 '18 at 20:08

answered Feb 21 '18 at 20:04

Rafael Paulino

570
2
9

Android studio is looking for a higher minimum API to use that call. Can you think of any alternatives? That API being 26 which means I'd have to limit my app to Android 8.0 and above which I'm not comfortable doing. – Joe Tobin Feb 21 '18 at 20:07
Look here: https://stackoverflow.com/questions/33802971/alternative-for-string-join-in-android – Rafael Paulino Feb 21 '18 at 20:09

score 0 · Answer 2 · answered Feb 21 '18 at 20:25

0

  ingredients = ingredients.replace("[", "");
  ingredients = ingredients.replace("]", "");
  ingredients = ingredients.replace("\"", "");
  ingredients = ingredients.replace(",", "\n");

This works...

answered Feb 21 '18 at 20:25

Joe Tobin

482
3
12

Formatting a JSONArray in Java

2 Answers2