How can I subtract a datetime.now object with a datetime string?

Question

I have a server bot where I want to make a certain command usable only once every 24 hours. Each time the user uses the command, I store datetime.now in my SQL database in %H:M:%S format so the variable may looks like this:

b = "07:17:45"

I would like to somehow subtract that stored string with datetime.datetimenow() each time the user uses the command to get an output of the remaining time left to check if 24 hours has passed or not.

You should convert b to datetime and substract them and then add .total_seconds() <= 24*60*60 — Anton vBR, Feb 22 '18 at 20:01
Possible duplicate of [Convert TimeDiff to total seconds](https://stackoverflow.com/questions/5522031/convert-timediff-to-total-seconds) — Anton vBR, Feb 22 '18 at 20:02

Reck · Accepted Answer · 2018-02-22T20:47:27.250

3

You may want to use strptime,

from datetime import datetime
now = datetime.now()
then = datetime.strptime('07:17:45', '%H:%M:%S')
then = datetime.combine(now.date(), then.time())

delta = now - then
time_in_seconds = delta.total_seconds()
time_in_minutes = time_in_seconds / 60
time_in_hours = time_in_minutes / 60

edited Feb 22 '18 at 20:47

answered Feb 22 '18 at 20:10

Reck

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Hmm, interesting. Not wrong though. Some changes needed – Reck Feb 22 '18 at 20:16
@heemayl you may want to check **then** now. – Reck Feb 22 '18 at 20:40
Yeah my bad. Thanks @heemayl – Reck Feb 22 '18 at 20:47

How can I subtract a datetime.now object with a datetime string?

1 Answers1