Sort a list based on the sort indexes of another list

Question

I have two lists and I want to sort the one of them (scores) in reverse order and get the corresponding indexes in order to sort the second one (section_id).

For example:

section_id = [5, 6, 8, 14]
scores = [4, 11, 13, 7]

The new lists will be:

sorted_reverse_scores = [13, 11, 7, 4]
sorted_section_id = [8, 6, 14, 5]

Do you know how to achieve this?

Currently the only thing I do is:

sorted_reverse_scores = section_id.sort(reverse=True)

Jay Shankar Gupta · Accepted Answer · 2018-03-01T10:42:19.073

1

section_id  = [5, 6, 8, 14]
scores  = [4, 11, 13, 7]
sorted_reverse_scores =[]
sorted_section_id =[]
for i in sorted(zip(scores,section_id),reverse=True):
  sorted_reverse_scores.append(i[0])
  sorted_section_id.append(i[1])
print(sorted_reverse_scores)
print(sorted_section_id)

output

[13, 11, 7, 4] [8, 6, 14, 5]

edited Mar 01 '18 at 10:42

answered Mar 01 '18 at 10:34

Jay Shankar Gupta

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don't dump the code put some explaination – Arpit Solanki Mar 01 '18 at 10:34
My initial lists are `section_id` `and scores`. I want to get the `sorted_section_id` based on the `sorted_reverse_scores`. – zinon Mar 01 '18 at 10:36
I corrected the answer you can validate now @zinon – Jay Shankar Gupta Mar 01 '18 at 10:44

Sort a list based on the sort indexes of another list

1 Answers1