Python issues if/elif

Question

I'm trying to make this code work but I can't seem to find the right solution.

while True:
    tname = input("Please enter the unit of the temperature: ")
    list=["Celsius","Kelvin","Fahrenheit"]
    if tname == list[0] or list[1] or list[2]:
        break
    elif tname is not list[0] or list[1] or list[2]:
        print("Not a valid unit. Please try again.")

I want the program to stop whenever either Celsius, Kelvin or Fahrenheit is typed but the program stops regardless of what I write. Do you guys know to fix it? Thanks in advance

`if tname == list[0] or list[1] or list[2]:` is not interpreted by Python as it would be in English. Maybe `if tname == list[0] or tname == list[1] or tname == list[2]:` — roganjosh, Mar 01 '18 at 22:21
I can't seem to find any of the 100 dupes for this question... — Mad Physicist, Mar 01 '18 at 22:23
@MadPhysicist I actually sat and read the dupe title 5 times to make a mental note :P — roganjosh, Mar 01 '18 at 22:24

score 1 · Answer 1 · answered Mar 01 '18 at 22:21

1

The technically correct answer is that chaining comprehensions doesn't work like that; you have to do

if tname == list[0] or tname == list[1] or tname == list[2]:

But have you considered using in?

if tname in list:

or similarly:

if tname not in list:

Also, I'd advise against using list as the name of your list, as that's also the name of a type!

answered Mar 01 '18 at 22:21

ACascarino

4,340
1
13
16

This code is way simpler and easier to understand, and the best part is that it works :D Thanks a lot! – nostres97 Mar 01 '18 at 22:32

Python issues if/elif

1 Answers1