How to create list of lists after every nth item

Question

In python how can I create a list of lists after every 5th item?

my_list = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Expected output:

new_list = [['a', 'b', 'c', 'd', 'e'], ['f', 'g', 'h', 'i', 'j']....]

See the `grouper` recipe here: https://docs.python.org/3/library/itertools.html#itertools-recipes — Brad Solomon, Mar 01 '18 at 22:51

score 8 · Accepted Answer · answered Mar 01 '18 at 22:51

8

new_list = [my_list[i:i + 5] for i in xrange(0, len(my_list), 5)]

What's happening here is that takes chunks of data from 0 - 5, 5 - 10, etc. to create sub lists

answered Mar 01 '18 at 22:51

usernamenotfound

How did you know the OP was using Python2 – John La Rooy Mar 01 '18 at 23:13
I didn't. I was using python 2 – usernamenotfound Mar 01 '18 at 23:16
@JohnLaRooy How will it be different for Python3? – Hannan Mar 01 '18 at 23:51
I think xrange is not an option – usernamenotfound Mar 02 '18 at 00:00
1

@Hannan, In Python3, you would need to use `range` instead of `xrange` – John La Rooy Mar 02 '18 at 03:04
@JohnLaRooy Thx, I ended up fixing it myself. – Hannan Mar 02 '18 at 03:06

1 Answers1