regular expression for length 6 to 20 characters with upper and lower case alphabets and numeric character support

Question

this regex is used to test the password that support at least one lower case and upper case alphabets and numbers. this regex is not support 6 to 20 characters support.

/(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,}/

/*
 var result = /(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,}/;
 return result.test(value);
*/

*i want to change this regex*. Are you asking for permission? If so, go ahead. Are you asking how? Use your keyboard. — Ken White, Mar 02 '18 at 05:37
var result = /(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,20}/; return result.test(value); — vijay, Mar 02 '18 at 05:37
var result = /(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,20}/; return result.test(value); this supports more than 20 characters. — vijay, Mar 02 '18 at 05:44
You shouldn't limit passwords. Please refer to [Reference - Password Validation](https://stackoverflow.com/questions/48345922/reference-password-validation/) for more info — ctwheels, Mar 02 '18 at 16:25

score 1 · Accepted Answer · answered Mar 02 '18 at 05:53

Working Snippet

var password = prompt("Enter password", "1234567890Aa1234567890");

var regex = /^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{6,20}$/;

console.log("Password valid?: ", regex.test(password));

The regex had 2 things missing

The range {6,20}
Plus, the ^ and $, in the start and end of the regex. They signify, that the regex should apply end to end, and not a subset of the string.

regular expression for length 6 to 20 characters with upper and lower case alphabets and numeric character support

1 Answers1