Load a file content to python grid GUI

Question

I am not a developer, just a system admin, i have already written a python script to collect a bunch of network information to 4 files(1 file has 4 lines).

File content format:

Device A: Status OK
Devide B: Status Ok
Device C: Status OK
Devide D: Status  Failed

Now i hope somebody can help me to show the content of file to a grid(table) in python which 1 file to 1 one row and 1 columns is one line

P/s: I don't know about Python GUI programming so i just stop there and view file by manual

Thanks

can you post some examples? also what have you tried so far? — pro_cheats, Mar 04 '18 at 13:42
Here is a sample of the table which i want but i don't know how to load the content to it: https://bytes.com/topic/python/answers/882126-grid-view-table-list-tkinter — Toi Lee, Mar 04 '18 at 14:10

pro_cheats · Accepted Answer · 2018-03-04T14:31:40.333

1

Try this it worked for me-

filename contains 4 lines. It displays each line as a column in r number of rows.

Replace r by your number of files and input accordingly.

import Tkinter
root = Tkinter.Tk()

#reading lines from the file
lines = [line.rstrip('\n') for line in open('filename')]

for r in range(3):  #r-rows
    for c in range(4): #c-columns
        Tkinter.Label(root, text=lines[c],
                      borderwidth=1).grid(row=r, column=c)
root.mainloop()

Output -

Update -

for displaying headers -

import Tkinter
root = Tkinter.Tk()

lines = [line.rstrip('\n') for line in open('filename')]

for r in range(4):
    for c in range(5):
        #0th row 0th column, leave it empty
        if c==0 and r==0:
            pass

        #non-0th row non-0th column, fill with values
        elif r!=0 and c!=0:
            Tkinter.Label(root, text=lines[c-1],
                     borderwidth=1).grid(row=r, column=c)

        else: 
            #0th column, meaning ROW headers
            if c==0:
                Tkinter.Label(root, text="row"+str(r),
                          borderwidth=1).grid(row=r, column=c)

            #0th row, meaning COLUMN headers
            if r==0:
                Tkinter.Label(root, text="column"+str(c),
                          borderwidth=1).grid(row=r, column=c)


root.mainloop()

Output -

edited Mar 04 '18 at 14:31

answered Mar 04 '18 at 13:57

pro_cheats

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Thank so much, but i need some row title and column title too. This table is so simple – Toi Lee Mar 04 '18 at 14:04
Here is the one i hope to have https://bytes.com/attachments/attachment/2782d1267057367/entrygrid.gif – Toi Lee Mar 04 '18 at 14:08
@ToiLee please check my updated answer. Kindly mark it as an answer if that helped :) – pro_cheats Mar 04 '18 at 14:29
Thank you, how do it know which file to load ? i have 4 different file names – Toi Lee Mar 04 '18 at 14:31
add the *filenames* in an array, and iterate over the *filenames* in an outermost `for` loop. – pro_cheats Mar 04 '18 at 14:32
I am glad that it helped you, can you please accept it as an answer? Put green tick like this -> https://meta.stackexchange.com/a/5235 – pro_cheats Mar 04 '18 at 14:41
Hi, when i tried elif c==0 and r==2: ^ TabError: inconsistent use of tabs and spaces in indentation . Why was that ? – Toi Lee Mar 06 '18 at 03:17
Thats a syntax error. Pls refer https://stackoverflow.com/a/5685816/5213405 – pro_cheats Mar 06 '18 at 04:13

Load a file content to python grid GUI

1 Answers1