specific split with regex

Question

I have this regex, it's an exemple:

/par(tir|te|s)|(quitter.*maison)|((heure|quand).*(rendez-vous|journée))/i

I would like to split it by "|" in a regular expression but this character can't be inside parenthesis for the explode. So the expected result have to be that:

1: par(tir|te|s)
2: (quitter.*maison)
3: ((heure|quand).*(rendez-vous|journée))

My mind is in trouble, someone can help me?

It's done yet, the regex in example is input and the second quote is expected output... — Hugo Giffard, Mar 04 '18 at 17:50

score 0 · Accepted Answer · answered Mar 04 '18 at 17:53

With a huge help from this old question, I was able to construct this regex.
It matches parenthesis with their content, including preceding text:

(?:\w+)?\((?:[^()]*|\((?:[^()]*|\([^()]*\))*\))*\)

However I must say that nested parenthesis are super hard to handle with regular expressions.

score 0 · Answer 2 · answered Mar 04 '18 at 17:54

0

You can split on this regex, which achieves precisely the output you specified from the input sample provided:

/\|(?!(?:\w+\|?)+\))/ig

answered Mar 04 '18 at 17:54

score 0 · Answer 3 · answered Mar 04 '18 at 17:54

0

You can try this regex /\|(?![^\(]*\))/g

const str = '/par(tir|te|s)|(quitter.maison)|((heure|quand).(rendez-vous|journée))/i';
console.log(str.split(/\|(?![^\(]*\))/g));

answered Mar 04 '18 at 17:54

Hassan Imam

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specific split with regex

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