Not able to parse JSON in php with numeric key

Question

This is my code which is giving error

Parse error: syntax error, unexpected '24' (T_LNUMBER), expecting identifier (T_STRING) or variable (T_VARIABLE) or '{' or '$' in C:\xampp\htdocs\block_gecko\front\index.php on line 186

echo '<td style="font-size: 120%;">' .$character->24hour . '</td>';

Syscall · Accepted Answer · 2018-03-04T23:32:43.013

1

PHP variable cannot starts with a numeric character. Try this:

$var = '24hour' ;
echo '<td style="font-size: 120%;">' .$character->$var . '</td>';

Example :

$json = json_decode('{"24hour":"test"}');
$key = "24hour";
echo $json->$key; // "test"

Or convert your JSON as array (json_decode($data, true)) and use :

echo '<td style="font-size: 120%;">' .$character['24hour'] . '</td>';

Another way (Thanks @mickmackusa) :

$json = json_decode('{"24hour":"test"}');
var_dump($json->{'24hour'});

edited Mar 04 '18 at 23:32

answered Mar 04 '18 at 23:15

Syscall

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@mickmackusa Oh! Sorry, didn't take care about that. – Syscall Mar 04 '18 at 23:19
No worries. Just know that there was a third option to solve this. Wrap in `{}`. – mickmackusa Mar 04 '18 at 23:19
@mickmackusa Right! I always forget this one. Thank you! – Syscall Mar 04 '18 at 23:21
it is not a duplicate question i have checked that question but didnt find the answer like this :/ – block Gecko Mar 04 '18 at 23:21
@blockGecko It's also works. Check the last way of the updated answer. – Syscall Mar 04 '18 at 23:24
@syscall yup that also works :P my mistake :P – block Gecko Mar 04 '18 at 23:26
@blockGecko you're welcome :) – Syscall Mar 04 '18 at 23:29

Not able to parse JSON in php with numeric key

1 Answers1