Loop over multiple file extensions from bash script

Question

I need a bash script for use in the Linux terminal which should go something like:

#!/bin/bash 

for textgrid_file in ./*.TextGrid and for wav_file in ./*.wav
do 
   praat --run pitch.praat "$textgrid_file" "$wav_file" >> output.txt
done

I.e. I need to iterate through pairs of files with extensions .textgrid and .wav because in my Praat script pitch.praat I have two arguments to pass. How can I implement it via bash scripting?

Possible duplicate of [Matching files with various extensions using for loop](https://stackoverflow.com/q/6223817/608639), [for loop for multiple extension and do something with each file](https://stackoverflow.com/q/12259331/608639), etc. — jww, Aug 19 '18 at 06:43

score 2 · Accepted Answer · answered Mar 05 '18 at 05:31

2

You can use an array support to iterate over first glob pattern and use 2nd file from array:

waves=(*.wav)

k=0
for textgrid_file in *.TextGrid; do
    praat --run pitch.praat "$textgrid_file" "${waves[k++]}" >> output.txt
done

answered Mar 05 '18 at 05:31

anubhava

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score 1 · Answer 2 · answered Mar 05 '18 at 05:38

If I understand you right, both filename share the same basename.

#!/bin/bash 
for textgrid_file in ./*.TextGrid 
do 
    name=$(basename $textgrid_file .TextGrid)
    wfile="$name.wav"
    praat --run pitch.praat "$textgrid_file" "$wfile" >> output.txt
done

Extract the common basename with basename.

Loop over multiple file extensions from bash script

2 Answers2

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