Convert items in a list element to a list

Question

I am forced to use comma separation in one of my input arguments to separate multiple values. So I end up with

my_string = ['a,b,c']

How can I convert this so that

my_new_string = ['a', 'b', 'c']

`my_string` is a `list`, is there any scenario where it should hold more than one string? — Szabolcs, Mar 05 '18 at 10:14
Possible duplicate of [How to convert comma-delimited string to list in Python?](https://stackoverflow.com/questions/7844118/how-to-convert-comma-delimited-string-to-list-in-python) — Artier, Mar 05 '18 at 10:19
Why this `argparse` tag ? Can you explicit what's your use case ? It may helps people to provide better answer :) — NiziL, Mar 05 '18 at 10:19
It's not a duplicate question, since it's a string contained in a list... Anyway, apologies to all for calling it my_string - I should have called it my_list...! — Jepper, Mar 05 '18 at 10:54
@NiziL the use case is that the script is called from Jenkins, using Jenkins shell implemention. It's challenging to call the python script with a single space delimited argument without Jenkins injecting quotes, thus the second item in the space delimited argument is being interpreted as a new argument. Comma separating the input arg thus means Jenkins argument parsing does not interfere. — Jepper, Mar 05 '18 at 10:59

score 6 · Accepted Answer · answered Mar 05 '18 at 10:14

6

One possible way:

my_new_string = my_string[0].split(',')

answered Mar 05 '18 at 10:14

Szabolcs

Yuankun · Answer 2 · 2018-03-05T10:52:56.893

-1

Try this one-liner:

my_new_string = [x for y in my_string for x in y.split(',')]

edited Mar 05 '18 at 10:52

answered Mar 05 '18 at 10:15

Yuankun

given that this question is tagged with `argparse` I don't think that this is the behavior OP is looking for. – Ma0 Mar 05 '18 at 10:17

score -1 · Answer 3 · answered Mar 05 '18 at 10:54

-1

Try this one-liner:

print(list(my_string[0].split(',')))

answered Mar 05 '18 at 10:54

DD.amor

3 Answers3