JQuery Select 4 Minimum Value from Array List

Question

I am trying to grab 4 Minimum values from a array list.

Example

var ArrayList =[2,3,4,76,23,14,99,54,21]

I would like to grab 4 Numbers so result should be 2,3,4,14

Thanks in advance.

A quick search for "Sort an array" and "Get first X from array" should solve this. — DBS, Mar 05 '18 at 16:30
`var res = [ArrayList[0],ArrayList[1],ArrayList[2],ArrayList[5]];` — Kevin B, Mar 05 '18 at 16:38

score 0 · Answer 1 · answered Mar 05 '18 at 16:32

0

Try This:

var array =[2,3,4,76,23,14,99,54,21];
var newarray=[];
var min;
for(i=0;i< 4;i++){
    min = Math.min.apply(Math,array); 
    newarray.push(min);
    array.splice(array.indexOf(min), 1);
}
alert(newarray);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>

answered Mar 05 '18 at 16:32

Tasos Fel

331
2
6

what the actual... – Neoares Mar 05 '18 at 16:34
"Try this" is not a good answer, explain what's going on! (also, using a static index in a loop typically is bad practice) – Sterling Archer Mar 05 '18 at 16:35

score 0 · Answer 2 · answered Mar 05 '18 at 16:35

0

first sort the list from least to greatest and splice the resulting string from the index 4 to the length of the array to get the minimum values

function myFunction() {
    arrayList.sort(function(a,b){ return (a-b)}).splice(4,arrayList.length);
}

answered Mar 05 '18 at 16:35

Lokesh Podipireddy

1
1

JQuery Select 4 Minimum Value from Array List

2 Answers2