get word after a specific string androidstudio

Question

my problem is that I have a string called url which has an extructure like the following https://www.ejemplo.com.co, and I need to extract only the text after "https: // www.", that is what I serves is "ejemplo.com.co", of course I do not know the url as it changes constantly.

Hint: look at the `split` and `substring` methods. – Mar 06 '18 at 16:43 — , Mar 06 '18 at 16:43

Mamun Kayum · Accepted Answer · 2018-03-06T19:22:11.153

0

Use the following:

    public String retrieveStr(String url) throws MalformedURLException {
       URL aURL = new URL(url);
       String desireStr  = aURL.getHost().split("\\.")[1];
      return desireStr;
  }

use this

edited Mar 06 '18 at 19:22

answered Mar 06 '18 at 17:28

Mamun Kayum

161
7

Thank you very much, but I would miss a part, taking into account that I already have after the puneto, as I do to only hold the part after the next point. I mean what would happen before the point, eg: ejemplo.com.co, I just want "example" – Nelson Redondo Barros Mar 06 '18 at 18:01
you mean "ejemplo"? Do you want only "ejemplo" , please clarify – Mamun Kayum Mar 06 '18 at 18:07
yes, let's give a practical example, this is the url: https://stackoverflow.com/questions/5414657/, what I want to know is "stackoverflow" – Nelson Redondo Barros Mar 06 '18 at 19:02
use the updated code in the answer box. Hope this will work :-) – Mamun Kayum Mar 06 '18 at 19:23
Good to know it works.. please upvote the answer :-). – Mamun Kayum Mar 06 '18 at 19:51

get word after a specific string androidstudio

1 Answers1