PHP Count Array Elements

Question

hi can someone explain why this would return "An array consists of 0 elements." :

$arr = array(1,3,5); 
$count = count($arr); 
if ($count = 0) { echo "An array is empty."; } else { echo "An array has $count elements."; }

By the way, this is one a quiz i'm working through and i'm not sure why this is the correct answer?

score 8 · Accepted Answer · answered Feb 06 '11 at 15:26

8

You are assigning $count to 0 in your conditional statement

Instead of...

if ($count = 0)

Do this

if ($count === 0)

answered Feb 06 '11 at 15:26

jondavidjohn

4

yes, check the docs here for a full explanation ... http://php.net/manual/en/language.operators.comparison.php – jondavidjohn Feb 06 '11 at 15:48

score 0 · Answer 2 · answered Jan 27 '17 at 07:48

Whenever you are going to check one logic means, check twice if we are using correct operators.

Most of them doing the same mistake like ,

if ($count = 0)   // here you are assigning the value to $count variable

Assign the values instead of compare the values.

if ($count == 0)  // here variable is compared

We can use more operators for comparing the logical condition.Such like ( >, <, >=, <=, == )

2 Answers2