Format Python List using re

Question

How can I format this string in a list from :

('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')

to :

('1496','8584','172','5988','7184','704','3448','6580','8504')

I think the way is to use re.sub() but I'm having trouble with the '\n' not escaping

You mean this string-'1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n' — Abhisek Roy, Mar 07 '18 at 17:01
So yes... by the way. You say you need a list `[...]`, but you are using a tuple `(...)`, can you clarify? — Olivier Melançon, Mar 07 '18 at 17:07
@Olivier: I suppose that tommy45 doesn't know difference between tuple and list in python. — TigerTV.ru, Mar 07 '18 at 17:35

Olivier Melançon · Answer 1 · 2018-03-07T17:47:29.750

3

You do not need re.sub, str.split will suffice.

t = ('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')

out = t[0].split()

# out : ['1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504']

If you want it exactly in the format you provided, you can cast back to a tuple. Note that when you use (...) you are creating a tuple and not a list as you mentionned.

out = tuple(t[0].split())

# out : ('1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504')

edited Mar 07 '18 at 17:47

answered Mar 07 '18 at 17:01

Olivier Melançon

21,584
4
41
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why is `t` a tuple? it adds unnecessary complexity, just start with a string as in the question. – avigil Mar 07 '18 at 17:03
1

@avigil Because the question has been edited, I just did a rollback to preserve the initial intent which is to have a string inside a list/tuple. – Olivier Melançon Mar 07 '18 at 17:20

Abhisek Roy · Answer 2 · 2018-03-07T17:10:19.917

1

Hope this works-

a='1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n'
b=a.split()
print(b)

Output-

['1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504']

The a.split() splits the string by every occurrence of \n.

edited Mar 07 '18 at 17:10

answered Mar 07 '18 at 17:02

Abhisek Roy

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12
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Or just use `.split()` to use consecutive whitespace characters as a single delimiter and then you won't end up with a trailing empty item. Should work fine for the OPs example. – Jon Clements Mar 07 '18 at 17:07
Well said. Thanks. I edited to include your comment. – Abhisek Roy Mar 07 '18 at 17:09
@Olivier Let the user clarify. – Abhisek Roy Mar 07 '18 at 17:20

score 0 · Answer 3 · answered Mar 07 '18 at 17:02

Instead of re.sub, use re.findall to grab every run of digits:

import re
s = ('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')
new_s = tuple(i for b in map(lambda x:re.findall('\d+', x), filter(None, s)) for i in b)

Output:

('1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504')

TigerTV.ru · Answer 4 · 2018-03-07T17:39:31.493

It's very simple. Use split function for strings.

#!/usr/bin/python
s = ('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')
output=s[0].split()
print(output)

output you expected as list:

['1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504']

If you want to get a tuple, use tuple function to convert.

#!/usr/bin/python
s = ('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')
output=tuple(s[0].split())
print(output)

output as a tuple:

('1496', '8584', '172', '5988', '7184', '704', '3448', '6580', '8504')

Differences between tuple and list in python you can get here.

score 0 · Answer 5 · answered Mar 08 '18 at 12:02

0

This code resolved my problem

output = ('1496\n8584\n172\n5988\n7184\n704\n3448\n6580\n8504\n', '')
output = str(output)
output = re.sub('[^a-zA-Z0-9 .]|n','',output)
output = output.split()
print output

answered Mar 08 '18 at 12:02

tommy45

3
1

Format Python List using re

5 Answers5