What is the way of clicking on links which could not be scrolled into view by Selenium + Python?

Question

This is piece if my code:

x=driver.find_element_by_xpath("""//*[@id="react-root"]/section/main/article/div[1]/div/div/div[1]/div[2]/a""")
x.click()

But, this error are occurred:

selenium.common.exceptions.ElementNotInteractableException: Message: Element <a href="/p/BgEcF34Fqf6/?tagged=fast"> could not be scrolled into view

Could you help me, please?

Did you try my answer? – Ratmir Asanov Mar 09 '18 at 13:08 — Ratmir Asanov, Mar 09 '18 at 13:08

score 6 · Accepted Answer · edited Nov 26 '19 at 21:48

Try JavaScript click:

from selenium.webdriver.remote.webelement import WebElement


def javascript_click(self, locator):
    element = None
    if isinstance(locator, str):
        element = self.find_element(locator)
    elif isinstance(locator, WebElement):
        element = locator

    if element is not None:
        self._driver.execute_script("arguments[0].click();", element)
    else:
        raise Exception("Could not click on locator " + element)

score 0 · Answer 2 · answered Mar 15 '18 at 12:21

I used this code which was worked carefully:

#Scroll down the page to load more posts
    driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
    time.sleep(10)
    j=j+1

Note that, you can generalize this scrolling into more that one reputation by use of for syntax.

What is the way of clicking on links which could not be scrolled into view by Selenium + Python?

2 Answers2