Python: open multiple txt file in a directory

Question

Hi i was going to open multiple txt files in a directory.

But i get error message of

File "testTopic.py", line 9, in <module>
with open(path +i, 'r') as f:
IOError: [Errno 2] No such file or directory:
'C:\Users\Documents\FP\TM\Export28011986676_10155756928931677.txt'

I did import os, and i trying to open files that ends with '.txt' where by my files all are 122343.txt, 344545.txt, 565464353.txt and carry on.

The code you posted does not contain the line the error message is pointing to. The code you posted has entirely different problems. — user2357112, Mar 11 '18 at 04:32
@user2357112 i have update my post, with a new error message — xxxSL, Mar 11 '18 at 04:40

DYZ · Answer 1 · 2018-03-11T05:02:30.273

1

You need to add a separator between the path and the file name:

path = "C:\Users\Documents\FP\TM\Export\\"

(Mind the slash at the end of the path.)

edited Mar 11 '18 at 05:02

answered Mar 11 '18 at 04:50

DYZ

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i tried , but it still cant. File "testTopic.py", line 5 path = "C:\Users\Documents\FP\TM\Export\" ^ SyntaxError: EOL while scanning string literal – xxxSL Mar 11 '18 at 05:01
My bad, I forgot to escape the slash. – DYZ Mar 11 '18 at 05:02

score 0 · Answer 2 · answered Mar 11 '18 at 05:00

0

or:

you can useing os.path.join

import os
os.path.join(path,i)

answered Mar 11 '18 at 05:00

python必须死

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Python: open multiple txt file in a directory

2 Answers2