Strings containing specific characters

Question

With this code what I am trying to do is not letting input names which don't contain vowels. It works when in the if there is only 1 vowel but when I try more than one it doesn't. I know the or in python means and/or. I have researched but I don't find an explanation why this happens. The code's sintaxis is ok. Can anyone tell me how the character's work?

var = False #Sets var to False

while var == False: #While var is False do this:

  name = str(input("What is your name? ")) #Input name and Print what is your name?

  if "a" or "e" or "i" or "o" or "u" in name: #If name contains a or e or i or o or u
    var = True #Set var to True

print ("Success") #Print Success

While the duplicate uses `==` as an example - it's the same if it used `in` as per your question. — Jon Clements, Mar 11 '18 at 12:07

score 2 · Accepted Answer · answered Mar 11 '18 at 11:55

2

var = False     
while var == False:     
  name = str(input("What is your name? ")) 
  if any(i in 'aeiou' for i in name.lower()):   
    var = True  

print ("Success")

answered Mar 11 '18 at 11:55

Smart Manoj

5,230
4
34
59

which is more effective "aeiouAEIOU" or name.lower()? – JaviHGM Mar 11 '18 at 12:05
For small names only, name.lower() is faster – Smart Manoj Mar 11 '18 at 12:15
Thanks as I want the least compilation time possible! – JaviHGM Mar 11 '18 at 12:17

Strings containing specific characters

1 Answers1