Remove character from string multiple times

Question

I have the following string, where I would like to remove all instances of EUR

var str = "200.00 EUR, 33.33 EUR, 100.95 EUR, 300 EUR";

So the output is:

var str = "200.00, 33.33, 100.95, 300";

I tried

var res = str.replace("EUR", "");

But that only removes EUR one time.

`str.replace(/EUR/g, "");` – gurvinder372 Mar 12 '18 at 15:13 — gurvinder372, Mar 12 '18 at 15:13

atiq1589 · Answer 1 · 2018-03-12T15:29:40.047

6

You can use regular expression to replace the string. Keep in mind string are immutable so original string will be unchanged.

var str = "200.00 EUR, 33.33 EUR, 100.95 EUR, 300 EUR";
var str1 = str.replace( /\s*EUR/g, "");
console.log(str1);

In string replace() it will search for the word 'EUR' and while it found the required value it will replace with the given value. As it found the required value and replace it. it wont search any further. That's why you need regular expression with /g flag. without /g flag it will work same

edited Mar 12 '18 at 15:29

answered Mar 12 '18 at 15:16

atiq1589

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Can you explain why replace("", ) passing a string is not working? – Ele Mar 12 '18 at 15:17
It search for the word 'EUR' and while it found it replace with the given value. As it found the required value and replace it. it wont search any further. Thats why you need regular expression with /g flag. without /g flag it will work same – atiq1589 Mar 12 '18 at 15:21
Please, put that comment in your answer – Ele Mar 12 '18 at 15:21
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Additionally, all regexs in these answers are wrong because you're not replacing the spaces between the number and comma. – Ele Mar 12 '18 at 15:23
Good job, upvoted! – Ele Mar 12 '18 at 15:25
@Ele thanks for pointing out about space. :) – atiq1589 Mar 12 '18 at 15:25
Take a look carefully `"200.00, 33.33, 100.95, 300"` – Ele Mar 12 '18 at 15:26
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maybe try -> `/\s*EUR/g` IOW: look for zero or more white-spaces followed by EUR. – Keith Mar 12 '18 at 15:28
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@Keith you're right. – Ele Mar 12 '18 at 15:29
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Now is perfect! `:)` – Ele Mar 12 '18 at 15:30
@Keith thanks for the correction. – atiq1589 Mar 12 '18 at 15:30

A l w a y s S u n n y · Accepted Answer · 2018-03-12T16:16:07.147

5

Try like this with a global replacement: by /g flag on replace()

Where, g is global case-sensitive replacement

var string  = '200.00 EUR, 33.33 EUR, 100.95 EUR, 300 EUR';
string = string.replace(/ EUR/g, '');
console.log(string);

Global replace can only be done with a regular expression. In the following example, the regular expression includes the global which permits replace() to replace each occurrence of ' EUR' in the string with ''

See Demo : https://jsfiddle.net/t7jz3h9k/11/

As per comment:

var string  = '200.00 EUR, 33.33 PND, 100.95 DLR, 300 EUR';
string = string.replace(/ EUR| PND| DLR/g, '');
console.log(string);

edited Mar 12 '18 at 16:16

answered Mar 12 '18 at 15:14

A l w a y s S u n n y

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Thanks! Will accept in 11 min ;-) – apples-oranges Mar 12 '18 at 15:16
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Can you explain why replace("", ) passing a string is not working? – Ele Mar 12 '18 at 15:16
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@apples-oranges OK, glad it works for you. Best of Luck – A l w a y s S u n n y Mar 12 '18 at 15:17
What about the space between the number and comma? This is the desired output `"200.00, 33.33, 100.95, 300"` @apples-oranges – Ele Mar 12 '18 at 15:24
@Ele Have you checked my edit? Please have a look and let me know is that ok? or may I need to change anything of my answer? – A l w a y s S u n n y Mar 12 '18 at 15:37
Good!, now it's an accpetable answer `:)` upvoted! – Ele Mar 12 '18 at 15:39
Thanks you Sir :) @Ele – A l w a y s S u n n y Mar 12 '18 at 15:39
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You can also see the solution in a more elegant way with such recurring patterns: `var str = "200.00 EUR, 33.33 EUR, 100.95 EUR, 300 EUR"; var result = str.split(',') .map(function(value, index) { return value.replace(/EUR/g,""); }) .join(','); console.log(result);` – Ashmah Mar 12 '18 at 15:40
Just a quik add on to this: what if I require to replace more than one character segment let's say: `200.00 EUR, 33.33 PND, 100.95 DLR, 300 EUR` – apples-oranges Mar 12 '18 at 16:09
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You can try quickly like this `string.replace(/ EUR/g, '').replace(/ PND/g,'').replace( /DLR/,'');` – A l w a y s S u n n y Mar 12 '18 at 16:11
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@apples-oranges see my edit because the quick way I suggested on comment is not very efficient. Plz see my update – A l w a y s S u n n y Mar 12 '18 at 16:16
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In my solution you can replace `value.replace(/EUR/g,"");` with `value.replace(/(EUR|PND|DLR)/g,"");` – Ashmah Mar 13 '18 at 01:41

score 2 · Answer 3 · answered Mar 12 '18 at 15:14

2

Easy, str.replace(/EUR/g, '');

answered Mar 12 '18 at 15:14

Drewness

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Can you explain why replace("", ) passing a string is not working? – Ele Mar 12 '18 at 15:16

Remove character from string multiple times

3 Answers3