how can i shuffles 7-digit number randomly in java

Question

like this :

Sample run:
Please enter a number: 1234567
The shuffled number is: 4356271
Sample run:
Please enter a number: 1000001
The shuffled number is: 0100100

Welcome to Stack Overflow! Please visit the [help], take the [tour] to see what and [ask]. Do some research, search for related topics on SO; if you get stuck, post a [mcve] of your attempt, noting input and expected output. — mplungjan, Mar 13 '18 at 16:06
While I agree with the close, I disagree with the duplicate question. — AntonH, Mar 13 '18 at 16:08
@AntonH See the list of dupes now. I can add JavaScript if needed — mplungjan, Mar 13 '18 at 16:31

score -1 · Answer 1 · answered Mar 13 '18 at 16:06

-1

Converting the number in a String use this method passing the string to it!

public void shuffle(String input){
        List<Character> characters = new ArrayList<Character>();
        for(char c:input.toCharArray()){
            characters.add(c);
        }
        StringBuilder output = new StringBuilder(input.length());
        while(characters.size()!=0){
            int randPicker = (int)(Math.random()*characters.size());
            output.append(characters.remove(randPicker));
        }
        System.out.println(output.toString());
    }

answered Mar 13 '18 at 16:06

SmoggeR_js

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How do you prompt for the number and who says OP actually MEANT JAVA – mplungjan Mar 13 '18 at 16:07
NOTE : I want to shuffle integer not arrays – kaicode_ Mar 13 '18 at 16:14
you can convert an integer to String, pass it to this method and transform the returned string to integer again.... – SmoggeR_js Mar 14 '18 at 09:21

how can i shuffles 7-digit number randomly in java

1 Answers1