foreach loop value outside of the loop

Asked Mar 15 '18 at 05:55

Active Mar 15 '18 at 06:14

Viewed 51 times

PHP return foreach loop value outside of the loop

$checkmissing = array();
if ($data){
    foreach ( $data as $curDay ){
        $checkmissing['value1'] = $curDay['value1'];
        $checkmissing['value2'] = $curDay['value2'];
        $checkmissing['value3'] = $curDay['value3'];
        $checkmissing['value4'] = $curDay['value4'];
        $checkmissing['value5'] = $curDay['value5'];
        $checkmissing['value6'] = $curDay['value6'];
        $checkmissing['value7'] = $curDay['value7'];
    }
}
return $checkmissing;

I try this it not return anything

edited Mar 15 '18 at 06:13

Phil

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asked Mar 15 '18 at 05:55

Learning

Refer this: https://stackoverflow.com/questions/5631962/php-variable-scope. – Adi Mar 15 '18 at 06:13
show your `$data` array. – Salim Ibrohimi Mar 15 '18 at 06:14
3

How are you verifying that it is _"not returning anything"_? Is `$data` an array? Where is it defined? – Phil Mar 15 '18 at 06:14
If you have $data array, you should use count in if condition like `if(count($data) > 0){ ...}` – Nagesh Katke Mar 15 '18 at 06:42

foreach loop value outside of the loop

0 Answers0