Find string beetwen first occurence of word and before first occurence of special character

Question

I have following log string and I need to get from them only MedSoftware part, which means

after .com\
before first occurence of \

SERVERNAME2018-03-08 18:40:28 File: "x:_default\app.address.com\MedSoftware.data\BackEnd.Technical.Dictionaries.Service-180308182311\Web.config", Name: "dictionaries_data_product", CS: "###connectionStrings.dictionariesdataproduct.connectionString" info: Format of the initialization string does not conform to specification starting at index 0. 6069

Now my regex looks like this:

((?<=.com\\).*(?=\\))

and catches all after .com but goes to LAST occurence of \

score -1 · Answer 1 · answered Mar 16 '18 at 11:50

-1

You can use ((?<=.com\\)[^\\]*(?=\\))

I basically replaced .* by [^\\]* so that it stops at the first occurence of \.

Demo

answered Mar 16 '18 at 11:50

Zenoo

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after adding `[^\\]*` you don't need to keep `(?=\\)` – Rehan Haider Mar 16 '18 at 11:55
Depends if OP wants to only match `.....com\xxx\ ` and not `.....com\xxx` – Zenoo Mar 16 '18 at 11:56
You are correct :) – Rehan Haider Mar 16 '18 at 11:56

user unknown · Answer 2 · 2018-03-16T12:03:17.580

-1

\.com\\([^\\]+)\\.*

Imho you don't need something to capture the first com specifically, because that's what RE's normally do anyhow. And if you capture anything but backslashes, that doesn't need greedy-specifiers either. Only the backslashes which need masking, as well as the literal dot, are a bit tricky.

The capturing group \1 or $1 or whatever it is on powershell, contains MedSoftware now.

Demo

edited Mar 16 '18 at 12:03

answered Mar 16 '18 at 11:57

user unknown

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Find string beetwen first occurence of word and before first occurence of special character

2 Answers2