Java, strange timestamp format in microsecond?

Question

How can I convert the following timestamp "2012-02-22T16:46:28.9870216+00:00" into a timestamp readable and processable by Java without losing any accuracy? what its data format?? for example about my goal, I receive 2 messages, read the timestamp in each message (as it written in my example above) compare between two timestamps to determine which is the old between them

by noting that the question below does not match what I need, it is different where they speak about timestamp format is different of 2012-02-22T16:46:28.9870216+00:00 which I did not know about it Converting ISO 8601-compliant String to java.util.Date

I don't know really how to deal with it in Java, if you can help please ? — Sarru Uken, Mar 18 '18 at 14:23
After the seconds you have microseconds and then time zone. And what do you mean by readable, also if you want to make the date 'shorter' you cannot do it without lossing precision (you could clarify if you don't mind for instance loose microsecond precision) — Jose Da Silva Gomes, Mar 18 '18 at 15:05
thank you @JoseDaSilva the answer number 1 below by gil.fernandes it was exactly what I need — Sarru Uken, Mar 18 '18 at 15:37
Possible duplicate of [Converting ISO 8601-compliant String to java.util.Date](https://stackoverflow.com/questions/2201925/converting-iso-8601-compliant-string-to-java-util-date) — Thomas Fritsch, Mar 18 '18 at 15:41

gil.fernandes · Accepted Answer · 2018-03-18T16:49:14.950

You can parse it with this format: DateTimeFormatter.ISO_OFFSET_DATE_TIME.

public static void main(String[] args) throws IOException {
    String str = "2012-02-22T16:46:28.9870216+00:00";
    DateTimeFormatter dtf = DateTimeFormatter.ISO_OFFSET_DATE_TIME;
    System.out.println(dtf.parse(str));
}

If you run this code, you will see on the console:

{OffsetSeconds=0, InstantSeconds=1329929188},ISO resolved to 2012-02-22T16:46:28.987021600

Update:

Here is an updated response which shows how to convert the string to a LocalDateTime and allows date comparisons:

public static void main(String[] args) throws IOException {
    String str = "2012-02-22T16:46:28.9870216+00:00";
    DateTimeFormatter dtf = DateTimeFormatter.ISO_OFFSET_DATE_TIME;
    LocalDateTime lds = LocalDateTime.parse(str, dtf);
    System.out.println(lds);
    String str2 = "2012-02-22T16:46:28.9970430+00:00";
    String str3 = "2012-02-22T16:46:29.0270266+00:00";
    LocalDateTime lds2 = LocalDateTime.parse(str2, dtf);
    LocalDateTime lds3 = LocalDateTime.parse(str3, dtf);
    System.out.println(lds2.compareTo(lds3));
    System.out.println(lds3.compareTo(lds2));
}

Update 2:

If you want to print out a date in this format you have to use java.time.OffsetDateTime, like so:

public static void main(String[] args) throws IOException {
    OffsetDateTime now = OffsetDateTime.now();
    DateTimeFormatter dtf = DateTimeFormatter.ISO_OFFSET_DATE_TIME;
    System.out.println(dtf.format(now));
}

This prints out:

2018-03-18T16:46:46.715Z

only one question? if you can put in your code part about how to compare between two timestamps for example this "2012-02-22T16:46:28.9970430+00:00" and this "2012-02-22T16:46:29.0270266+00:00" — Sarru Uken, Mar 18 '18 at 14:54
@SarruUken You can create a LocalDateTime object which you then compare. See updated response. — gil.fernandes, Mar 18 '18 at 15:00
Mr. @gil.fernandes please, everything is ok now, but I can not figure out how to get the (current timestamp) using exactly the same timestamp format ? can you please help me in this matter? — Sarru Uken, Mar 18 '18 at 16:39
you are great Mr. @gil.fernandes thank you very much from my heart — Sarru Uken, Mar 18 '18 at 16:53

Java, strange timestamp format in microsecond?

1 Answers1